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3 years ago

6

A new basketball costs $25.00 at the sporting goods store. If the store is having a going-out-of-business sale and everything is

60% off, what is the actual cost of the basketball?

1 answer:

lara31 [8.8K]3 years ago

6 0

I think the actual cost is 41.66

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Abigail”s car used 9 gallons of gas to travel 378 miles. How many gallons of gas would she need to travel 210 miles?

lara [203]

Answer:

5

Step-by-step explanation:

378 divided by 9 = 42

210 divided by 42=5

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3 years ago

X + y = 0 2x – y = -6 solve by graphing

kap26 [50]

Answer:

SOLVE FOR X, Y

x=12

y=−6

Step-by-step explanation:

5 0

3 years ago

How to create an equation for function m? I wrote the right equation as a guess, but I don't understand it.

AfilCa [17]

Answer:

$h(x)=2(x + 3)^{\frac{1}{2} }$

Step-by-step explanation:

Parent function of the square root function has been given as,

f(x) = $x^{\frac{1}{2} }$

If the graph of the given function is stretched vertically by the scale factor = g(x) = $k(x^\frac{1}{2})$

If the graph is shifted 3 units to the left,

h(x) = $k(x + 3)^{\frac{1}{2} }$

Since, the graph of the function passes through a point (-2, 2),

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2 = k

Therefore, the function is $h(x)=2(x + 3)^{\frac{1}{2} }$ .

7 0

3 years ago

Not sure f either of my answers would satisfy the question in the second picture

xz_007 [3.2K]

$\bf \begin{array}{llll}
tan(\alpha)=-\cfrac{80}{15}\qquad II\\\\
x=-15\\
y=8\\
r=17
\end{array} \qquad \qquad 
\begin{array}{llll}
cos(\beta)=\cfrac{5}{6}\qquad I\\\\
x=5\\
y=\sqrt{11}\\
r=6
\end{array}\\\\
-----------------------------\\\\
sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})
\\\\\\
sin({{ \alpha}} + {{ \beta}})=\cfrac{8}{17}\cdot \cfrac{5}{6}+\cfrac{-15}{17}\cdot \cfrac{\sqrt{11}}{6}\implies \cfrac{40-15\sqrt{11}}{102}$

$\bf cos({{ \alpha}} + {{ \beta}})= cos({{ \alpha}})cos({{ \beta}})- sin({{ \alpha}})sin({{ \beta}})
\\\\\\
\cfrac{-15}{17}\cdot \cfrac{5}{6}-\cfrac{8}{17}\cdot \cfrac{\sqrt{11}}{6}\implies \cfrac{-75-8\sqrt{11}}{102}$

$\bf tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}
\\\\\\
tan({{ \alpha}} + {{ \beta}}) = \cfrac{-\frac{8}{15}+\frac{\sqrt{11}}{5}}{1-\left( -\frac{8}{15}\cdot \frac{\sqrt{11}}{5} \right)}\implies 
\cfrac{\frac{-8+3\sqrt{11}}{15}}{1+\frac{8\sqrt{11}}{75}}
\\\\\\
tan({{ \alpha}} + {{ \beta}}) =\cfrac{\frac{-8+3\sqrt{11}}{15}}{\frac{75+8\sqrt{11}}{75}}\implies \cfrac{-8+3\sqrt{11}}{15}\cdot \cfrac{75}{75+8\sqrt{11}}
\\\\\\
$

$\bf tan({{ \alpha}} + {{ \beta}}) =\cfrac{-8+3\sqrt{11}}{1}\cdot \cfrac{3}{75+8\sqrt{11}}\implies \cfrac{15\sqrt{11}-40}{75+8\sqrt{11}}$

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4 years ago

Which number line correctly shows -3-(1.5)

katovenus [111]

The first choice is correct because negative goes left and both numbers are negative!

3 0

3 years ago