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Liula [17]
3 years ago
9

Find a ⋅ b.

Mathematics
1 answer:
sashaice [31]3 years ago
4 0

Answer:

Step-by-step explanation:

a.b=5(4)+2(5)=20+10=30

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Find all values of x that make the triangles congruent. Explain your reasoning.
RSB [31]

Answer:

x = \frac{4}{5},5

Step-by-step explanation:

If both the triangles ΔABC and ΔBCD are congruent,

Corresponding sides of both the triangles will be proportional.

\frac{AB}{BD}=\frac{AC}{CD}

\frac{5x}{3x+10}=\frac{5x-2}{4x+3}

5x(4x + 3) = (5x - 2)(3x + 10)

20x² + 15x = 15x² + 50x - 6x - 20

20x² + 15x = 15x² + 44x - 20

20x² - 15x² = 44x - 15x - 20

5x² = 29x - 20

5x² - 29x + 20 = 0

5x² - 25x - 4x + 20 = 0

5x(x - 5) - 4(x - 5) = 0

(5x - 4)(x - 5) = 0

x=\frac{4}{5},5

3 0
3 years ago
the population of masterton was 23 000 in 2012. Assume that Masterton population increases at a rate of 2% per year. Write an eq
Oksanka [162]
So, let's first focus on the first year:

the population then would be: 23000* (100+2)%

100% is the old population the 2% is the incease, so in total it's 102%, or 1.02 - the same number written differently.

So it will be 23000*1.02

After two years it will be 23000*1.02*1.02, and so on

so after x years it will be:

y=23000*1.02^{z}
8 0
3 years ago
HELP ME PLEASE Before they graduate from Great Lakes High School, all 12th grade students fill out a survey about their future c
Fed [463]

Answer:

178/662

Step-by-step explanation:

(a)The probability that a student will begin college during the summer semester and attend an in-state college.

P(A student will begin college during the summer semester and attend an in-state college)

3 0
3 years ago
Read 2 more answers
Given that 'n' is any natural numbers greater than or equal 2. Prove the following Inequality with Mathematical Induction
Oliga [24]

The base case is the claim that

\dfrac11 + \dfrac12 > \dfrac{2\cdot2}{2+1}

which reduces to

\dfrac32 > \dfrac43 \implies \dfrac46 > \dfrac86

which is true.

Assume that the inequality holds for <em>n</em> = <em>k </em>; that

\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k > \dfrac{2k}{k+1}

We want to show if this is true, then the equality also holds for <em>n</em> = <em>k</em> + 1 ; that

\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k + \dfrac1{k+1} > \dfrac{2(k+1)}{k+2}

By the induction hypothesis,

\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k + \dfrac1{k+1} > \dfrac{2k}{k+1} + \dfrac1{k+1} = \dfrac{2k+1}{k+1}

Now compare this to the upper bound we seek:

\dfrac{2k+1}{k+1}  > \dfrac{2k+2}{k+2}

because

(2k+1)(k+2) > (2k+2)(k+1)

in turn because

2k^2 + 5k + 2 > 2k^2 + 4k + 2 \iff k > 0

6 0
2 years ago
Read 2 more answers
No
zhuklara [117]
It’s B 20 students I am sure that’s correct
5 0
3 years ago
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