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kondaur [170]
3 years ago
6

Find the value of x a. 2 b. 4 c. 6 d. 8

Mathematics
1 answer:
tiny-mole [99]3 years ago
8 0

Answer:

B, 4

Step-by-step explanation:

To do this you can use the Pathagaryos thereom a^2+b^2=c^2

So we have (x-2)^2+x^2=20

We can expand (x-2)^2 and get

x^2-4x+4

so we have x^2 -4x +4 + x^2=20

We can combine like terms and subtract 20 from both sides to get

2x^2-4x-16=0

We can factor this and get (2x+4)(x-4)

which means that x=4 and -2

Obviously the length can't be a negative and so we reject x= -2 and we get x=4

We can double check it and see that

(4-2)^2+4^2=20

and it does

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Jordan starts his day by doing his exercises. Jordan jumps rope for 10 minutes and lifts weights for 30 minutes. Jordan runs 10
romanna [79]

Answer:

35

Step-by-step explanation:

0.25 x 140 = 35

8 0
3 years ago
A pizzeria sells a round pizza with a diameter of 16 inches. Another pizzeria sells a large square pizza with a side length of 1
ankoles [38]

Answer:

pizzeria1

Step-by-step explanation:

Given data

pizzeria1

Diameter=16in

Radius= 16/2= 8in

Area= πr^2

Area= 3.132*8^2

Area= 201.09 in^2

pizzeria2

Diameter=15in

Radius= 15/2= 7.5in

Area= πr^2

Area= 3.132*7.5^2

Area= 176.74n^2

4 0
3 years ago
How do I solve this problem
quester [9]
I think x equals 54


Hope this helps
4 0
3 years ago
A item on sale costs 80% of the original price.if the original price was $15 what is the sale price?
Effectus [21]

Answer:

$3

Step-by-step explanation:

Original price - Discounted price

= $15 - ($15 × 80%)

= $15 - ($15 × 80/100)

= $15 - ($1200/100)

= $15 - $12

= <u>$</u><u>3</u>

So, the sale price is $3

<em>Hope it helps and is useful</em><em> </em><em>:</em><em>)</em>

8 0
3 years ago
Which line(s) intersect the parabola y = x^2 − 3x + 4 at two points? Select all that apply. A. y = –3x + 2 B. y = –3x + 3 C. y =
TEA [102]

Answer:

C and D

Step-by-step explanation:

Equating the line A and the parabola, we get

-3x + 2 = x² - 3x + 4

0 = x² - 3x + 4 +3x - 2

0 = x² + 2

-2 = x²

which has no real solutions. Then, the line A and the parabola don't intersect each other.

Equating the line B and the parabola, we get

-3x + 3 = x² - 3x + 4

0 = x² - 3x + 4 + 3x - 3

0 = x² + 1

-1 = x²

which has no real solutions. Then, the line B and the parabola don't intersect each other.

Equating the line C and the parabola, we get

-3x + 5 = x² - 3x + 4

0 = x² - 3x + 4  + 3x - 5

0 = x² - 1

1 = x²

√1 = x

which has 2 solutions, x = 1 and x = -1. Then, the line C and the parabola intersect each other.

Equating the line D and the parabola, we get

-3x + 6 = x² - 3x + 4

0 = x² - 3x + 4  + 3x - 6

0 = x² - 2

2 = x²

√2 = x

which has 2 solutions, x ≈ 1.41 and x ≈ -1.41. Then, the line D and the parabola intersect each other.

4 0
3 years ago
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