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Sphinxa [80]
3 years ago
3

Square BCDE with vertices B(-6,7),C(-2,6),D(-3,2), and E(-7,3) in the y-axis. find the reflection?

Mathematics
1 answer:
GarryVolchara [31]3 years ago
5 0

Answer:

The vertices of the square B'C'D'E' are B'(x, y) = (6,7), C'(x,y) = (2, 6), D'(x,y) = (3,2) and E'(x,y) = (7,3)

Step-by-step explanation:

From Geometry we notice that a reflection with axis of symmetry on y-axis is represented by the following formula:

(x',y') = (-x, y), \forall \,x,y\,\in\mathbb{R}

Thus, the vertices of the square B'C'D'E' are B'(x, y) = (6,7), C'(x,y) = (2, 6), D'(x,y) = (3,2) and E'(x,y) = (7,3)

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What is the area of the rectangle?
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Read 2 more answers
<img src="https://tex.z-dn.net/?f=3%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%202%20%5Cfrac%7B1%7D%7B4%7D%20%20-%201%20%5Cfrac%7B1%7D%
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Answer:

Step-by-step explanation:

Step 1: Convert into improper fractions

Step 2: Find  least common denominator and find equivalent fractions

Step 3 : Do the required operation

3\frac{1}{2}+2\frac{1}{4}-1\frac{1}{2}=\frac{7}{2}+\frac{9}{4}-\frac{3}{2}\\

Least common denominator of 2 , 4 = 4

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3 years ago
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