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Readme [11.4K]
2 years ago
5

What’s the following sum?

Mathematics
2 answers:
erma4kov [3.2K]2 years ago
6 0

\huge{ \orange{ \boxed{ \bold{6 \sqrt{5} }}}}

EXPLAINATION :

<u>By</u><u> </u><u>following</u><u> </u><u>the</u><u> </u><u>rule</u><u> </u><u>in</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>sum</u><u> </u><u>or</u><u> </u><u>difference</u><u> </u><u>of</u><u> </u><u>similar</u><u> </u><u>radicals</u>

<u>\green{a \sqrt{c} \:  +  \: b \sqrt{c}  \:  = (a + b) \sqrt{c} }</u>

Viefleur [7K]2 years ago
4 0

Answer:

3.73

Step-by-step explanation:

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Mrs. Cerra planted 4 ⅞ acres of wheat and 1 ⅝ acres of corn. How much more wheat did she plant than corn?
alukav5142 [94]
We can subtract the acres of corn from the acres of wheat.
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She planted 3 1/4 more acres of wheat than corn.
3 0
3 years ago
Let f(x)=x^3-x-1
alexira [117]
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To find the gradient of the tangent, we must first differentiate the function.

f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1

The gradient at x = 0 is given by evaluating f'(0).

f'(0) = 3(0)^2 - 1 = -1

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

y = -x + c

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

f(0) = (0)^3 - (0) - 1 = -1

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

y = -x + c \\\\ -1 = -(0) + c \\\\ -1 = c \\\\ \text{Equation of tangent is } \boxed{y = -x - 1}
6 0
3 years ago
timothyis re-arranging his marbles collection. he has 5 identical blue marbles, five green and 3 black. he can fit excactly 5 ma
Lerok [7]
-- He must have at least one of each color in the case, so the first 3 of the 5 marbles in the case are  blue-green-black.

Now the rest of the collection consists of

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                    2 black

and there's space for 2 more marbles in the case.

So the question really asks:  "In how many ways can 2 marbles
be selected from 4 blue ones, 4 green ones, and 2 black ones ?"

-- Well, there are 10 marbles all together. 
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the second one can be any one of the remaining 9 .

Total number of ways to pick 2 out of the 10  =  (10 x 9)  =  90 ways.

-- BUT ... there are not nearly that many different combinations
to wind up with in the case.    

The first of the two picks can be any one of the 3 colors,
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6 0
3 years ago
To boost holiday sales, a jewelry store in Bismarck, North Dakota, is advertising the following promotion: "If more than seven i
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Answer:

What is the question?

7 0
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