Isn’t this 12/4 of a mile of thread every hour? If the factory produces 3/4 of a mile of thread every 1/4 of an hour, then all you need to do is 3/4 x 4. 1/4 is like .25 so to make a whole number, you have to do .25 x4 which makes the whole. I don’t know if my explanation is correct or not but I do believe my answer is. (12/4 is 3)
Answer:
first one: x<9 second: x<3.5 or 7/2
Step-by-step explanation:
first: substract 3 from both sides
second: substract 5 and then divide by 2
Hope this helps but try to do process of elimination.
Answer:
3.375
Step-by-step explanation:
Answer:
<em>Choice: B.</em>
Step-by-step explanation:
<u>Operations With Functions</u>
Given the functions:
![f(x)=\sqrt[3]{12x+1}+4](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4)

The function (g-f)(x) can be obtained by replacing both functions and subtracting them as follows:

![(g-f)(x)= \log(x-3)+6 - (\sqrt[3]{12x+1}+4)](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%28%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4%29)
Operating:
![(g-f)(x)= \log(x-3)+6 - \sqrt[3]{12x+1}-4](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D-4)
Joining like terms:
![\boxed{(g-f)(x)= \log(x-3) - \sqrt[3]{12x+1}+2}](https://tex.z-dn.net/?f=%5Cboxed%7B%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D%2B2%7D)
Choice: B.