Draw a line representing the rise and a line representing the run of the line State the slope of the line in simplest form

Find the final amount for the investment given you initially have $5500 earning

stich3 [128]

Is the final value
P is the initial principle
r is the (annual) interest rate (as a decimal)
t is time (years)

10500%2Ae%5E%28%28.0625%2A25%29%29

5 0

3 years ago

You invest $15,000 to start a hot dog stand at the local sports complex. It costs you $.65 to produce each hot dog. How many hot

SCORPION-xisa [38]

Answer:

Below is the procedure to find the answer: 30,000 hot dogs.

Explanation:

The <em>average cost </em>is found dividing the total cost by the number of hot dogs:

$Average\text{ }cost=Total\text{ }cost/Number\text{ }of\text{ }hot\text{ }dogs$

The total cost is the the sum of amount that you invest plus the product of the cost of producing each hot dog times the number of hot dogs:

$Total\text{ }cost=investment+Number\text{ }of\text{ }hot\text{ }dogs\times cost\text{ }to\text{ }produce\text{ }each\text{ }hot\text{ }dog$

Substitute the values:

$Total\text{ }cost=15,000+0.65x\\ \\ Averate\text{ }cost=(15,000+0.65x)/x=1.15$

Where x is the number of hot dogs.

Solve for x from the equation:

$(15,000+0.65x)/x=1.15\\ \\ 15,000+0.65x=1.15x\\ \\ 15,000=1.15x-0.65x\\ \\ 15,000=0.5x\\ \\ 15,000/0.5=x\\ \\ 30,000=x\\ \\ x=30,000$

Which shows you how you can find that the answer is 30,000 hot dogs.

8 0

3 years ago

In the Ma-and-Pa grocery store, shelf-space is limited and must be used effectively to increase profit. Two-cereal items, Grano

insens350 [35]

Answer:

No. 2/3 of the space to Grano and 1/3 of the space to Wheatie.

Step-by-step explanation:

Allocating about 57% to Wheatie and 43% to Grano, means to allocate 60(.57)=34.2 ft2 of Wheatie and 60(.43)=25.8 ft2 of Grano. In that case there would be 34.2/.4=85.5≈85 boxes of Wheatie and 25.8/.2=129 boxes of Grano. The total profit would be 129(1)+85(1.35)=$243.75

Best option:

200 Granos boxes and 50 Wheaties boxes on the shelf.

200(.2)=40ft^2 will allocate Granos boxes

50(.4)=20ft^2 will allocate Wheaties boxes.

This means that 40/60=2/3=66.6% of the space will allocate Granos boxes and 20/60=1/3=33.3% of the space will allocate Wheaties boxes.

The total profit would be 200(1)+50(1.35)=$267.5

EXTRA:

This is a optimization problem.

Let X1 be the number of Granos boxes

Let X2 be the number of Wheaties boxes

Objective:

Max Z=1(X1)+1.35(X2)

Subjecto to

0.2(X1)+0.4(X2)<=60,

X1<=200,

X2<=120,

X1,X2>=0.

You can solve it using the simplex method. Check the image for more details.

5 0

3 years ago

21➗7= , ✖️7=21 what is the meaning of the unknown factor and quotient?

viktelen [127]

21 divided by 7 equals 3 and 3 x 7 is 21 the missing factor is 3 and the missing quotient is 21

5 0

4 years ago

GIVING BRAINLIESTTTTT

andreev551 [17]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

# Contracting parallel lines

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2. Place the pin of the compass at point C and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

# Constructing a perpendicular line through a point on the line

- Given line AB and point P lies on it

1. Place your compass pin at P and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3. Place the compass pin on point C and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

* Lets find the same steps in the constructions

∵ In first construction we put the pin of the compass at point C which lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is: "Place the compass on a point on the original line"

6 0

3 years ago