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mina [271]
3 years ago
7

Solve for x. 2x + 5 = x - 8

Mathematics
1 answer:
Gemiola [76]3 years ago
7 0
2x+5=x-8
-x on both sides
x+5=8
-5 on both sides
x=-13
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Solve for y. <br><br> xy + p = 5<br><br> A) y = 5 - p - x<br> B) y = (5-p)/x<br> C) y = 5 - px
Damm [24]
Minus p both sides
xy=5-p
divide both sides by x
y=(5-p)/x

B
6 0
3 years ago
Find the area of the triangle
kupik [55]
Area = 1/2 * base * height 
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3 years ago
Find the x-intercept and y-intercept of the liné.<br> - 6x + 5y = 21
Hunter-Best [27]

Answer:

x=-3.5 or -7/2 (same thing)

y=21/5

Step-by-step explanation:

x intercept is when y=0

y intercept is when x=0

so

x intercept is

-6x=21

x=21/-6

x=-3.5

y intercept is

5y=21

y=21/5

7 0
3 years ago
What is the solution to the equation 6y –2(y + 1) = 3(y – 2) + 6?
tensa zangetsu [6.8K]

Answer:

y = 2

Step-by-step explanation:

6y - 2(y + 1) = 3(y - 2) + 6

6y - 2y - 2 = 3y - 6 + 6

6y - 2y - 2 = 3y

4y - 2 = 3y

4y - 2 + 2 = 3y + 2

4y = 3y + 2

4y - 3y = 3y - 3y + 2

y = 2

6 0
3 years ago
Adult female height is normally distributed with a mean of 65.3 inches and a standard deviation of 2.32 inches. a) If an adult f
emmasim [6.3K]

Answer:

0.0423 is the probability that the adult female has a height less than 61.3 inches.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 65.3 inches

Standard Deviation, σ = 2.32 inches

We are given that the distribution of adult female height is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(adult female has a height less than 61.3 inches)

P( x < 61.3) = P( z < \displaystyle\frac{61.3 - 65.3}{2.32}) = P(z < -1.7241)

Calculation the value from standard normal z table, we have,  

P(x < 61.3) =0.0423 = 4.23\%

0.0423 is the probability that the adult female has a height less than 61.3 inches.

5 0
3 years ago
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