Help ASAPpppppppppp plsssssss and ty

Rewrite in simplest radical form 1/x^-3/6.

Aneli [31]

$\cfrac{1}{x^{- \frac{3}{6} }} = \cfrac{1}{x^{- \frac{1}{2} }} =x^{ \frac{1}{2} }= \sqrt{x}$

6 0

3 years ago

explain how you can tell the difference between the half inch and quarter inch marks when measuring an object with a ruler

svlad2 [7]

Answer:

You will know it is an inch ruler because it will have 12 lines that denote inches on ... In the first inch, these marks will mark 1/4, 1/2, 3/4, and 1 ...

7 0

3 years ago

Maya is trying to break or tie the league record for home runs in her softball league. She solved the inequality mc019-1.jpg to

Lelechka [254]

The correct answer would be letter C. She needs to either break or tie the record. The less than or equal to symbol in the original inequality would be her scoring less or tying the record. Using the greater than or equal to sign would represent her breaking the record or tying with it. Hope this helped.

7 0

3 years ago

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The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.

erma4kov [3.2K]

Answer:

CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

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Step-by-step explanation:

Given:

Radius of the cylinder = 7 cm
Height of the cylinder = 10 cm

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To Find:

Curved surface area
Volume

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Solution:

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Using formula:

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA \: of \: cylinder = 2\pi rh}}}}}} \: \star \\ \\$

Substituting the required values: 

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$\dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times 22 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 44 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 440 \: {cm}^{2} \\ \\ \\$

Now,

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}= \pi {r}^{2} h}}}}}} \: \star \\ \\ \\$

Substituting the required values, 

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$\dashrightarrow \: \: \sf Volume {(cylinder)}= \dfrac{22}{7} \times {(7)}^{2} \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= \frac{22}{7} \times 49 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 1540 {cm}^{3} \\ \\ \\$

Hence,

CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

8 0

2 years ago

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The distance a spring will stretch varies directly with how much weight is attached to the spring. If a spring stretches 6 inche

Iteru [2.4K]

The correct answer is:

C.4.1 in

Explanation:

We will use a proportion for this problem.

In the first ratio, we have 6 inches: 80 pounds. This can also be written as 6/80.

For the second ratio, we do not know the length; this is x. The weight is 55; this gives us x/55.

This makes our proportion

6/80 = x/55

Cross multiplying, we have

6(55) = 80(x)

330 = 80x

Divide both sides by 80:

330/80 = 80x/80

4.125 = x

This means the answer is 4.1.

6 0

3 years ago

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