Answer:
You didn't provide the complete question as the radius or diameter of the circle isn't given. Please check the explanation below to see how to approach such questions.
Step-by-step explanation:
Area of a circle has a formula and it is given as:
Area = 
where
is a constant and has a value of 3.14 or 22/7,
r is the radius of the circle (i.e the line drawn from the center of the circle to any point on the circle).
radius, r = diameter/2.
Example 1: Find the area of a circle with radius 7meters (7m) and correct to the nearest whole number. Use 3.14 or 22/7 for pi.
Solution:

NB: The unit of area is always in square units. In our case square meters
Example 2: Find the area of a circle with diameter 7feet(7ft). Use 3.14 or 22/7 for pi.
Solution:

But we were given the diameter not the radius.
Remember that I earlier said that radius, r = diameter/2 = 


So, if you have questions that ask for area, ensure you have the radius and if the diameter is given instead of the radius, carry out the neccessary calculation i.e. Diameter/2 to obtain the radius and use the area formula.