If i have a 15 question test and the test is worth 25 points how many points is each question worth

Mamont248 [21]

Question 4 is Choice A
Question 5 is Choice B
Question 6 is Choice C
Question 7 is Choice B

These are relatively simple it’s just understanding the relations of x and y values :)

3 0

2 years ago

You are given the following information obtained from a random sample of 5 observations. 20 18 17 22 18 At 90% confidence, you w

Margaret [11]

Answer:

a

The null hypothesis is

$H_o : \mu = 21$

The Alternative hypothesis is

$H_a : \mu< 21$

b

$\sigma_{\= x} = 0.8944$

c

$t = -2.236$

d

Yes the mean population is significantly less than 21.

Step-by-step explanation:

From the question we are given

a set of data

20 18 17 22 18

The confidence level is 90%

The sample size is n = 5

Generally the mean of the sample is mathematically evaluated as

$\= x = \frac{20 + 18 + 17 + 22 + 18}{5}$

$\= x = 19$

The standard deviation is evaluated as

$\sigma = \sqrt{ \frac{\sum (x_i - \= x)^2}{n} }$

$\sigma = \sqrt{ \frac{ ( 20- 19 )^2 + ( 18- 19 )^2 +( 17- 19 )^2 +( 22- 19 )^2 +( 18- 19 )^2 }{5} }$

$\sigma = 2$

Now the confidence level is given as 90 % hence the level of significance can be evaluated as

$\alpha = 100 - 90$

$\alpha = 10$ %

$\alpha =0.10$

Now the null hypothesis is

$H_o : \mu = 21$

the Alternative hypothesis is

$H_a : \mu< 21$

The standard error of mean is mathematically evaluated as

$\sigma_{\= x} = \frac{\sigma}{ \sqrt{n} }$

substituting values

$\sigma_{\= x} = \frac{2}{ \sqrt{5 } }$

$\sigma_{\= x} = 0.8944$

The test statistic is evaluated as

$t = \frac{\= x - \mu }{ \frac{\sigma }{\sqrt{n} } }$

substituting values

$t = \frac{ 19 - 21 }{ 0.8944 }$

$t = -2.236$

The critical value of the level of significance is obtained from the critical value table for z values as

$z_{0.10} = 1.28$

Looking at the obtained value we see that $z_{0.10}$ is greater than the test statistics value so the null hypothesis is rejected

6 0

3 years ago

Make a box-and-whisker plot of the data. 60,63,53,66,65,58,51,55,58,51,58,62,53,66,61,51,65,52,54,50

gregori [183]

Answer:

Step-by-step explanation:

To do this by hand, first sort data (you can use wolfram to do this).

Then divide data into four parts.

50, 51, 51, 51, 52, 53, 53, 54, 55, 58, 58, 58, 60, 61, 62, 63, 65, 65, 66, 66

Minimum = 50

Q1 = (52+53)/2 = 52.5

Median = (58+58)/2= 58

Q3 = (62+63)/2 = 62.5

Maximum = 66

IQR = 62.5 - 52.5 = 10

Outlier is defined as a value x such that

x > Q3 + 1.5*IQR or x < Q1 - 1.5*IQR

=> There are no outliers.

3 0

3 years ago

Anwerrrrrrplzzzzzzzzzzzzz

aliina [53]

Answer:

53

Step-by-step explanation:

65=x+12

-12. -12

53=x

3 0

2 years ago

What is the length of u and v in this 30-60-90 triangle

qwelly [4]

Answer:

option 2

Step-by-step explanation:

Using trigonometric ratio:

$Cos \ 60 = \frac{adjacent } {hypotenuse} \\\\\frac{1}{2} = \frac{4}{u}\\\\1 \times u = 2 \times 4 \\\\u = 8$

Now using Pythagoras theorem we will find v

$8^2 = 4^2 + v^2\\\\64 = 16 + v^2\\\\v^2 = 64 - 16 \\\\v = \sqrt{48} = \sqrt{16 \times 3} = \sqrt{4^2 \times 3 } = 4\sqrt{3}$

8 0

2 years ago