1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
docker41 [41]
3 years ago
5

PLEASE HELP!

Mathematics
1 answer:
shepuryov [24]3 years ago
7 0
Well there is no picture but I think your answer should be <span><span>38/360 </span>∗100π </span>expressed as a decimal number..
D: 28.97 ft squared I believe is the answer
You might be interested in
How long will it take a person to walk from Toronto to
storchak [24]

Answer:

About 947 hours, walking at 5 km (3 miles)/hour.

Walking 8 hours /day [at that pace you would need to be an Olympic Athlete to keep up the pace] it will take about four months.

Walk slower, it will take longer.

4 0
2 years ago
Is this a function ? Yes or no and why or why not
never [62]

Answer:

Yes

Step-by-step explanation:

Yes it is a function, because graph is intersecting y - axis only once.

3 0
3 years ago
Use a calculator to find the square for 7.6​
natita [175]

Answer:

Using a calcuator, 7.6^{2} =57.76

6 0
2 years ago
Read 2 more answers
PLS HELP OLL GIVE BRAINLIEST
Rudiy27

Answer:

yes they are the same

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How would you determine the axis of symmetry in order to graph x^2 = 8y^2.
Tanya [424]
The picture illustrates the definition. The point P is a typical point on the parabola so that its distance from the directrix, PQ, is equal to its distance from F, PF. The point marked V is special. It is on the perpendicular line from F to the directix. This line is called the axis of symmetry of the parabola or simply the axis of the parabola and the point V is called the vertex of the parabola. The vertex is the point on the parabola closest to the directrix.

Finding the equation of a parabola is quite difficult but under certain cicumstances we may easily find an equation. Let's place the focus and vertex along the y axis with the vertex at the origin. Suppose the focus is at (0,p). Then the directrix, being perpendicular to the axis, is a horizontal line and it must be p units away from V. The directrix then is the line y=-p. Consider a point P with coordinates (x,y) on the parabola and let Q be the point on the directrix such that the line through PQ is perpendicular to the directrix. The distance PF is equal to the distance PQ. Rather than use the distance formula (which involves square roots) we use the square of the distance formula since it is also true that PF2 = PQ2. We get

<span>(x-0)2+(y-p)2 = (y+p)2+(x-x)2. 
x2+(y-p)2 = (y+p)2.</span>If we expand all the terms and simplify, we obtain<span>x2 = 4py.</span>

Although we implied that p was positive in deriving the formula, things work exactly the same if p were negative. That is if the focus lies on the negative y axis and the directrix lies above the x axis the equation of the parabola is

<span>x2 = 4py.</span><span>The graph of the parabola would be the reflection, across the </span>x<span> axis of the parabola in the picture above. A way to describe this is if p > 0, the parabola "opens up" and if p < 0 the parabola "opens down".</span>

Another situation in which it is easy to find the equation of a parabola is when we place the focus on the x axis, the vertex at the origin and the directrix a vertical line parallel to the y axis. In this case, the equation of the parabola comes out to be

<span>y2 = 4px</span><span>where the directrix is the verical line </span>x=-p and the focus is at (p,0). If p > 0, the parabola "opens to the right" and if p < 0 the parabola "opens to the left". The equations we have just established are known as the standard equations of a parabola. A standard equation always implies the vertex is at the origin and the focus is on one of the axes. We refer to such a parabola as a parabola in standard position.

Parabolas in standard positionIn this demonstration we show how changing the value of p changes the shape of the parabola. We also show the focus and the directrix. Initially, we have put the focus on the y axis. You can select on which axis the focus should lie. Also you may select positive or negative values of p. Initially, the values of p are positive. 

5 0
3 years ago
Other questions:
  • If cos Θ =-4/7 , what are the values of sin Θ and tan Θ?
    5·1 answer
  • If x2 + xy + y3 = 1, find the value of y''' at the point where x = 1.
    9·1 answer
  • Help help help help help
    14·2 answers
  • Rectangle A'B'C'D' is the image of rectangle ABCD after a dilation.
    9·2 answers
  • What are the intercepts of the graph of the equation 6 x − 1 . 5 y = 18?
    7·1 answer
  • Help on 3&amp;4 I don't get what in the Mumbo jumbo their talking about
    12·2 answers
  • A stamp has the Length of 1/2 cm and a width of 1 1/2 is the area of the stamps
    6·1 answer
  • I beg anybody please
    14·1 answer
  • Devon has $200 in his savings account. He has to withdraw $8 every week to pay his friend back for some video games. The video g
    15·1 answer
  • Rachel bought a sweater at the sale price of $38. The original cost of the sweater was $52. What percent represents the discount
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!