<u>Included sides AE and BE</u> need to be given as congruent to prove that triangle AEC is congruent to triangle BED by the Angle-Side-Angle (ASA) Congruence Theorem.
According to the Angle-Side-Angle (ASA) Congruence Theorem, if two angles and an included side of a triangle is congruent to corresponding two angles and an included side of another triangle, both triangles can be proven to be equal or congruent to each other.
We are know the following from the given image:
<AEC = <BED (vertical angles are congruent)
<EAC = <EBD (congruent angle)
This implies that two angles (<AEC and <EAC) in triangle AEC are congruent to two corresponding angles (<BED and <EBD) in triangle BED.
Therefore, to prove that both triangles are congruent by ASA, we need to be given that the included sides AE and BE are congruent.
Learn more about Angle-Side-Angle (ASA) Congruence Theorem here:
brainly.com/question/23968808
Answer:
Step-by-step explanation:
volume of a pyramid is V=(lwh)/3
Answer:
Step-by-step explanation:
8x = 2 * 2 * 2 * x
6 = 2* 3
Greatest common factor = 2
8x + 6 = 2*4x + 2*3
= 2*(4x + 3)
Answer:
Step-by-step explanation:
Given: △ABC, BC>AC, D∈ AC , CD=CB
To prove: m∠ABD is acute
Proof: In ΔABC, the angle opposite to side BC is ∠BAC and the angle opposite to side AC is ∠ABC.
Now, it is given that BC>AC, then ∠BAC>∠ABC.. (1)
In ΔBDC, using the exterior angle property,
∠ADB=∠DBC+∠BCD
∠ADB=∠DBC+∠BCA
⇒∠ADB>∠BAC (2)
From equation (1) and (2), we get
∠ADB>∠BAC
⇒∠ADB>∠ABC
⇒DB>AB
Hence, m∠ABD is acute
