Question

Find an equation of the tangent line to the curve at the given point. y=secx (pi/3,2)

Answer 1

Base on the question where as asking to calculate the equation of the tangent line to the curve at the given point and base on the given data and in my further computation about the said given, I would say y = 2√(3)x + 2 - (2pi√(3))/3. I hope you are satisfied with my answer and feel free to ask for more