3 years ago

Find an equation of the tangent line to the curve at the given point. y=secx (pi/3,2)

1 answer:

7 0

Base on the question where as asking to calculate the equation of the tangent line to the curve at the given point and base on the given data and in my further computation about the said given, I would say <span>y = 2√(3)x + 2 - (2pi√(3))/3. I hope you are satisfied with my answer and feel free to ask for more </span>

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Describe the location of the point having the following coordinates. negative abscissa, zero ordinate between Quadrant II and Qu

Marianna [84]

Answer:

The location of the point is between Quadrant II and Quadrant III

Step-by-step explanation:

we know that

The abscissa refers to the x-axis and ordinate refers to the y-axis

in this problem we have

the coordinates of the point are $(-x,0)$