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forsale [732]
2 years ago
5

The amount of trout y (in tons) caught in a lake from 1995 to 2014 can be modeled by the equation y = -0.08x2 + 1.6x + 10, where

x is the number of years since 1995. When were about 15 tons of trout caught in the lake? The year and the year .
Mathematics
1 answer:
Lapatulllka [165]2 years ago
3 0
For this case, the first thing we want to do is substitute the value of y = 15 in the equation.
 We have then:
 15 = -0.08x ^ 2 + 1.6x + 10
 Rewriting we have:
 0 = -0.08x ^ 2 + 1.6x + 10 - 15
 0 = -0.08x ^ 2 + 1.6x - 5
 The solutions are:
 x1 = 3.876275643042054
 x2 = 16.123724356957947
 Nearest whole number:
 x1 = 4
 x2 = 16
 were about 15 tons of trout caught in the lake in the years:
 1995 + 4 = 1999
 1995 + 16 = 2011
 Answer:
 The year 1999 and the year 2011
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\qquad \qquad\huge \underline{\boxed{\sf Answer}}

<h3><u>Distance travelled each day is</u> : </h3>

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<h3><u>Explanation</u> : </h3>

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And if he travels same Distance each day, so let the Distance travelled on each day be x

According to question ~

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