Question

Please help!!! I’m so confused on how to solve this!

Answer 1

Let's first write the equation given

x²+6x-13=0

They have told us to use "Completing the square" method.

So we need write x²+6x-13 as a whole square.

x²+6x-13=0

x²+(2*3*x)-9-4 = 0

x²+(2*3*x)-3²=4

Now we can write the LHS as:

(x - 3)²=2²

Hence,

x-3 can either be 2 or -2

Now,

x - 3=2

x=5

Or,

x - 3=-2

x=1

Therefore now we know that x can either be 1 or  5. So the correct answer is  Option B.

Answer 2

Step-by-step explanation:

x squared+6x-13=0

carry over that into the other side of the equal sign and then make the other side of the equal sign a perfect square

x squared +6x+3 squared=13+9(3 squared)

find the square root of both sides

(x+3)=class plus or minus