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3 years ago

1,050 millimeters to meters

Mathematics

1 answer:

Scorpion4ik [409]3 years ago

3 0

1.05 meters
1 meter is 1000 millimeters

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Use the graph below to answer the following questions.

Maru [420]

Answer:

a) 3
b) x = {-3, -2, 2}

Step-by-step explanation:

Refer to attached for points

a) f(-1) = 3 as per graph

b) f(x) = 6

We add horizontal line through point y=6 to find intersections with the graph

Take x-values of those points. The points are x = -3, x = -2, x = 2

3 0

3 years ago

Bob is six years older than his sister, and the sum of their ages is 32. how old is bob?/search?q=david+is+38+years+old+and+his+

erica [24]

Bob's age is 22
And her sisters age is 14
If you'll add 22&14 the answer would be 36
And if you'll subtract 22&14 the answer would be 6

4 0

3 years ago

What fraction is equivalent to 30/360?

Firdavs [7]

Answer:

1/12

Step-by-step explanation:

Given that

30/360 to lowest fraction equivalent

Now, we can write 30 as 3×10

Also, we can write 360 as 36×10

Then, we have

(3×10)/(36×10)

Then, 10 cancel 10, we are left with

3/36

Also we can write 36 as 12×3

Then, we have

3/(12×3)

Also, 3 cancel 3, we are left with

1/12

Then the lowest fraction is 1 / 12

1/12

4 0

3 years ago

Read 2 more answers

The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide an

Firlakuza [10]

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Step-by-step explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

I.e L' = (w + 7) feet

∵ The area of deck = 116 feet²

So , L' × w' = 116 feet²

(w + 7)× (w + 4) = 116

Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w = $\dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, w = $\dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}$

Or, w = $\dfrac{-11\pm \sqrt{473}}{2}$

or, w = $\dfrac{-11\pm 21.7}{2}$

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

Answer

3 0

3 years ago

A part of the real number line is shown.

umka2103 [35]

Its R
you can just see in figure as square root of 50 is approximately around 7.07

7 0

3 years ago