0.13 <== the decimal is in the tenth place.
We could also say it is equal to
13/100
Or,
"C" 13%
I hope this helps!
~kaikers
Answer:
Step-by-step explanation:
Given that:
The numbers of the possible public swimming pools are 5
From past results, we have 0.007 probability of finding bacteria in a public swimming area.
In the public swimming pool, the probability of not finding bacteria = 1 - 0.007
= 0.993
Thus;
Probability of combined = Probability that at least one public
sample with bacteria swimming area have bacteria
Probability of combined sample with bacteria = 1 - P(none out of 5 has
bacteria)
Probability of combined sample with bacteria = 1 - (0.993)⁵
= 1 - 0.9655
= 0.0345
Thus, the probability that the combined sample from five public swimming areas will show the presence of bacteria is 0.0345
From above, the probability that the combined sample shows the presence of bacteria is 0.0345 which is lesser than 0.05.
Thus, we can conclude that; Yes, the probability is low enough that there is a need for further testing.
Answer: The perimeter is 30ft.
Step-by-step explanation:
Let's define:
L = length of the longer side.
S = length of the shorter side.
P = perimeter
we know that for a common rectangle:
P = 2*S + 2*L
We aso know that:
L = 2ft + (1/3)*P
S = (1/10)*P
L = S + 9ft.
So we have a system, let's find the perimeter only using this system (So i will ignore the equation for the perimeter of a rectangle)
First, we can replace the third equation in the first equation, now we have a system with only two equations:
S + 9ft = 2ft + (1/3)*P
S = P/10
Now we can replace the second equation in the first equation, and get:
P/10 + 9ft = 2ft + P/3
Now let's solve this for P.
9ft - 2 ft = P/3 - P/10
7ft = P( 1/3 - 1/10) = P*( 10/30 - 3/30) = P*(7/30)
(30/7)*7ft = P = 30ft.
The perimeter is 30ft.
let's multiply both sides by the LCD of all fractions, in this case is 4, just to do away with the denominators for a few seconds
![\bf f(x) = \cfrac{1}{4}x^2+\cfrac{1}{2}x-\cfrac{35}{4}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{4}}{4[f(x)]=4\left( \cfrac{1}{4}x^2+\cfrac{1}{2}x-\cfrac{35}{4} \right)} \\\\\\ 4f(x) = x^2+2x-35\implies 4f(x) = (x+7)(x-5) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill f(x) = \cfrac{1}{4}(x+7)(x-5)~\hfill](https://tex.z-dn.net/?f=%5Cbf%20f%28x%29%20%3D%20%5Ccfrac%7B1%7D%7B4%7Dx%5E2%2B%5Ccfrac%7B1%7D%7B2%7Dx-%5Ccfrac%7B35%7D%7B4%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B4%7D%7D%7B4%5Bf%28x%29%5D%3D4%5Cleft%28%20%5Ccfrac%7B1%7D%7B4%7Dx%5E2%2B%5Ccfrac%7B1%7D%7B2%7Dx-%5Ccfrac%7B35%7D%7B4%7D%20%5Cright%29%7D%20%5C%5C%5C%5C%5C%5C%204f%28x%29%20%3D%20x%5E2%2B2x-35%5Cimplies%204f%28x%29%20%3D%20%28x%2B7%29%28x-5%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20f%28x%29%20%3D%20%5Ccfrac%7B1%7D%7B4%7D%28x%2B7%29%28x-5%29~%5Chfill)
Answer:
Sure I'll try to help!
(-3.14, -5)
Step-by-step explanation:
