A sample of 14 students was selected to estimate the average score in a given quiz. The average score in the sample is 2.14 with
1 answer:
The average score of the student in the class at a 99% confidence lies between 1.252 and 3.028
Explanation:
Given values are
n = 14 = 2.14 σ = 1.29 z value for 99% confidence = 2.576
The mean is known one
= (z σ/√14)
= (2.576 ×1.29÷√14)
= 2.576 × 0.345
= 0.888
= mean- 0.888 = 2.14 - 0.888 = 1.252
= mean+0.888 = 2.14 + 0.888 = 3.028
The average score of the students in the class at a 99% confidence lies between 1.252 and 3.028
You might be interested in
Amortizing a loan P over n periods at i% interest / period, the payment per period is given by:
In given situation,
P=20000
period=month
i=10%/12
n=5*12=60 months
A. monthly payment amount
to the nearest cent
B. EAR (effective annual rate)
the APR is 10%, but compounded monthly.
So
EAR=(1+i/12)^12-1
=(1+0.1/12)^12-1
=0.104713
=10.4713% (effective annual rate)
In given situation,
P=20000
period=month
i=10%/12
n=5*12=60 months
A. monthly payment amount
B. EAR (effective annual rate)
the APR is 10%, but compounded monthly.
So
EAR=(1+i/12)^12-1
=(1+0.1/12)^12-1
=0.104713
=10.4713% (effective annual rate)