A.The genotype frequencies can be determined by dividing the number of individuals with a genotype by the total number all the individuals.
FF genotype frequency:
98÷200=0,49. There are approximately 5 <span>homozygous dominant mice in 10.
Ff genotype frequency:
84</span>÷200=0,42. There are approximately 4 <span>heterozygous mice in 10.
ff genotype frequency:
18</span>÷200=0,09. There are approximately 1 <span>homozygous recessive mouse in 10.
B.To determine the frequency of an allele we can divide the number of times that the allele appears by the total number of alleles.
F allele frequency:
</span>

<span>=0.7
There are 7 F alleles in 10 random alleles.
f </span>allele frequency:

=0.3
There are 3 f alleles in 10 random alleles.<span>
</span>
Answer:
a. Aminopeptidase and e. Angiotensin converting enzyme (ACE)
Explanation:
Posttranslational modification includes the transfer or removal of functional groups.
Answer:
my best guess is number answer 2 and answer 4
because crows love to eat desert woodrats and for the last one i watched it in national geo, its like a cycle grass hopper died by a mouse dies by a rattle snake.