The first clue to this problem is that Bob has three kids in which the product of their ages is 72 and the sum is 14. From the factor tree, there are two combinations of the ages 2, 6, 6 and<span> 3,3,8. Last thing he said is that his youngest is named Justice. One combination has similar number in the set which means there are twins. The youngest means there can be only one child. Hence the ages of the children are 2,6,and 6. </span>
Answer:
If you want to know what the probability is to get at least one Heads, then that is the same as the probability of all the events (100%, or 1) minus the probability of getting all Tails.
There are 100 coins. 99 are fair, 1 is biased with both sides as heads. With a fair coin, the probability of three heads is 0.53=1/8. The probability of picking the biased coin: P(biased coin)=1/100.
Step-by-step explanation:
Hello!
If there is 4 faces and 1/4 chance of any side end up face down, we just have to decrease one chance, so, the chance of the face "2" does not end up face down is equal the sum of the chances of the others faces end up face down, so, we have: 3/4.
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The weight average of the coordinates is -4
<h3>How to determine the
weight average?</h3>
The complete question is given as:
The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. And we need to calculate the weight average
The given parameters are:
- Coordinate -6 has a weight of 3
- Coordinate 2 has a weight of 1.
The weight average is then calculated as:
Weight average = Sum of (Weigh * Coordinate)/Sum of Weights
So, we have:
Weight average = (-6 * 3 + 2 * 1)/(3 +1)
Evaluate the products
Weight average = (-18 + 2)/(3 +1)
Evaluate the sum
Weight average = -16/4
Evaluate the quotient
Weight average = -4
Hence, the weight average of the coordinates is -4
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<u>Complete question</u>
The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. Calculate the weight average
