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4 years ago

What are some prime numbers to create a product of four

1 answer:

8 0

Since a product in maths means the result after multiplying numbers, you need to multiply 2 prime numbers and get 4.

If we look at the prime numbers: 2, 3, 5, 7, 11, etc, we see that the only number we can multiply to get 4 is 2, or, in other words, the only multiplication of prime numbers we can do to get four is 2*2=4.

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Will mark correct answer branliest!!!

WITCHER [35]

Answer: A = 4 P = π PS = -π/2

<u>Step-by-step explanation:</u>

y = A sin(Bx - C) + D where

A is the amplitude
Period = 2π/B
Phase Shift = C/B
D is the vertical shift

Given: y = -4 sin(2x + π) - 3

A (amplitude) = 4 <em>the negative sign is a reflection, not amplitude</em>
B = 2
C = -π
D = -3

Amplitude = 4

$\text{Period}=\dfrac{2\pi}{B}\quad =\quad \dfrac{2\pi}{2}\quad =\quad \pi$

$\text{Phase Shift}=\dfrac{C}{B}\quad =\quad \dfrac{-\pi}{2}\quad =\quad -\dfrac{\pi}{2}$

4 0

3 years ago

Repartir 310 nueces entre tres personas de modo que la segunda reciba 20 menos que la primera y 40 mas que la tercera

almond37 [142]

Answer:

Step-by-step explanation:

625282629283637hshshs

3 0

3 years ago

A box contain 12 balls in which 4 are white 3 are blue and 5 are red.3 balls are drawn at random from the box.find the chance th

Anastasy [175]

Answer:

3/11

Step-by-step explanation:

From the above question, we have the following information

Total number of balls = 12

Number of white balls = 4

Number of blue balls = 3

Number of red balls = 5

We solve this question using combination formula

C(n, r) = nCr = n!/r!(n - r)!

We are told that 3 balls are drawn out at random.

The chance/probability of drawing out 3 balls = 12C3 = 12!/3! × (12 - 3)! = 12!/3! × 9!

= 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1/(3 × 2 × 1) × (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

= 220 ways

The chance of selecting 3 balls at random = 220

To find the chance that all the three balls are selected,

= [Chance of selecting (white ball) × Chance of selecting(blue ball) × Chance of selecting(red balls)]/ The chance/probability of drawing out 3 balls

Chance of selecting (white ball)= 4C1

Chance of selecting(blue ball) = 3C1 Chance of selecting(red balls) = 5C1

Hence,

= [4C1 × 3C1 × 5C1]/ 220

= 60/220

= 6/22

= 3/11

The chance that all three are selected is = 3/11

4 0

3 years ago

Need some help, please. :D

4vir4ik [10]

Answer: (P.s its very hard to write special characters here, i hope this helped though)

((−6d0)(g−3))(h2)

d−5m3g−2h5

−6d5g2h2

g3h5m3

−6d5

gh3m3

4 0

3 years ago

The moon is a sphere with radius of 959 km. Determine an equation for the ellipse if the distance of the satellite from the surf

Sergeeva-Olga [200]

Answer:

$\frac{x^2}{1316^2}+\frac{y^2}{1669^2}=1$

Step-by-step explanation:

An ellipse is the locus of a point such that its distances from two fixed points, called foci, have a sum that is equal to a positive constant.

The equation of an ellipse with a center at the origin and the x axis as the minor axis is given by:

$\frac{x^2}{b^2}+\frac{y^2}{a^2} =1 \\\\where\ a>b$

Since the distance of the satellite from the surface of the moon varies from 357 km to 710 km, hence:

b = 357 km + 959 km = 1316 km

a = 710 km + 959 km = 1669 km

Therefore the equation of the ellipse is:

$\frac{x^2}{1316^2}+\frac{y^2}{1669^2}=1$

5 0

3 years ago