Remark
First of all, you should notice that the number you want must end in 5 to get a remainder of 5. That's because your divisors all end in 0.
Step One
Factor the 3 divisors
40: 2 * 2 * 2 * 5
50: 2 * 5 * 5
60: 2 * 2 * 3 * 5
Step Two
Using these factors, find the LCM
There are 3 twos, 1 Three, and 2 fives.
The LCM is 8*3*25 = 600
Step Three
Find the first number over 1000 that is divisible by 600. That should be 1200 which is 600 * 2
So the answer to your question is 1205
Answer:
Step-by-step explanation:
1*12 + 2*2 + 3*6 = 12 + 4 +18 = $34
.80 x 520= 416. ——————————-
<em>Greetings from Brasil...</em>
Here is the problem:
[(15X - 8)/3] + [(9X - 3)/2]
<em>Let's multiply everything by 6</em>
[6.(15X - 8)/3] + [6.(9X - 3)/2]
[2.(15X - 8)] + [3.(9X - 3)]
30X - 16 + 27X - 9
<h3>57X - 25</h3>
Answer:
0.2+0.28= 0.48
Step-by-step explanation:
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