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a_sh-v [17]
3 years ago
15

How do you solve trigometric ratios?

Mathematics
1 answer:
Cloud [144]3 years ago
3 0
Choose which trig ratio to use. - Choose either sin, cos, or tan by determining which side you know and which side you are looking for. - Solve the resulting equation to find the length of the side. Step 1: Choose which trig ratio to use.
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8x + 4 = 44<br>What is x?<br><br>Test
ale4655 [162]
8x = 44 -4
8x = 40
x = 40/8
x = 5
8 0
3 years ago
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26/x=-13 <br> I need a false answer and what it would equil
cupoosta [38]
Correct answer:
26 = -13x
X = -2

if you need a false answer, make up any number!
7 0
2 years ago
Suppose that the functions q and r are defined as follows.
satela [25.4K]

Answer:

(r o g)(2) = 4

(q o r)(2) = 14

Step-by-step explanation:

Given

g(x) = x^2 + 5

r(x) = \sqrt{x + 7}

Solving (a): (r o q)(2)

In function:

(r o g)(x) = r(g(x))

So, first we calculate g(2)

g(x) = x^2 + 5

g(2) = 2^2 + 5

g(2) = 4 + 5

g(2) = 9

Next, we calculate r(g(2))

Substitute 9 for g(2)in r(g(2))

r(q(2)) = r(9)

This gives:

r(x) = \sqrt{x + 7}

r(9) = \sqrt{9 +7{

r(9) = \sqrt{16}{

r(9) = 4

Hence:

(r o g)(2) = 4

Solving (b): (q o r)(2)

So, first we calculate r(2)

r(x) = \sqrt{x + 7}

r(2) = \sqrt{2 + 7}

r(2) = \sqrt{9}

r(2) = 3

Next, we calculate g(r(2))

Substitute 3 for r(2)in g(r(2))

g(r(2)) = g(3)

g(x) = x^2 + 5

g(3) = 3^2 + 5

g(3) = 9 + 5

g(3) = 14

Hence:

(q o r)(2) = 14

8 0
3 years ago
Evaluate 3x for x = -2, x = 1, and x = 3.
jok3333 [9.3K]

Answer:

A) 1/9, 3, 27

Step-by-step explanation:

i think you mean 3^x (and not 3x).

because otherwise none of the answer options withdraw makes any sense.

3^-2 = 1/(3²) = 1/9

3¹ = 3

3³ = 27

3 0
2 years ago
Can someone please help me with this?? I NEED THIS ASAP
salantis [7]

Answer:

hi ate you know crush kita <3

( ˘ ³˘)♥︎

4 0
3 years ago
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