Answer:

Step-by-step explanation:

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
Answer:
76,000,000
Step-by-step explanation:
Look at the 100,000 place and see whether to round up or down - 8 is larger than 5, therefore 75,000,000 gets rounded up to 76,000,000
<h2>
Explanation:</h2>
Let's use a trial and improvement method to find this solution.
Step 1. Let's choose x = 8.5
Substituting into the equation:

Step 2. Let's choose x = 8.4
Substituting into the equation:

Step 3. Let's choose x = 8.3
Substituting into the equation:

Since the sign of the equation changes from positive to negative when evaluating from 8.4 to 8.3, then x = 8.3 seems to be a reasonable value. Finally, the solution to 1 decimal place is:
Answer:
the dog was born on july 30th so the dog would be 3 months and a week old
Step-by-step explanation: