Answer:
67,365,043,200
Step-by-step explanation:
A coin toss has 2 possible outcomes. A coin tossed 3 times has 2³ = 8 possible permutations.
A standard die has 6 possible outcomes. A die rolled 4 times has 6⁴ = 1296 possible permutations.
The number of ways 4 cards can be chosen from a deck of 52 without replacements is 52×51×50×49 = 6,497,400.
The total number of possible outcomes is:
8 × 1296 × 6,497,400 = 67,365,043,200
Well you can simplify them by dividing by there greatest common factor.
In this case they can both divide by 12!
Thats the biggest number they can divide by...
Soo..
36 ÷ 12 = 3
----------------
48 ÷ 12 = 4
So your answer is 3/4!
Good Luck! :)
Answer:
The right answer is "0.70".
Step-by-step explanation:
The given query seems to be incomplete. Please find below the attachment of the full query.
By using the Bayes' theorem, we get
⇒ 
By putting the values, we get
![=\frac{[P(2)+P(3)]}{[1-P(0)-P(1)]}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5BP%282%29%2BP%283%29%5D%7D%7B%5B1-P%280%29-P%281%29%5D%7D)



Answer: it should be 565.5
Step-by-step explanation:
Answer:
$51.2
Step-by-step explanation:
4 x 12.8 = 51.2