Question

By the third day of a particular week, 2 accidents have already occurred in the intersection. What is the probability that there will be less than a total of 4 accidents during that week

Answer 1

Answer:

The right answer is "0.70".

Step-by-step explanation:

The given query seems to be incomplete. Please find below the attachment of the full query.

By using the Bayes' theorem, we get

⇒  $P[(X$

By putting the values, we get

                                     $=\frac{[P(2)+P(3)]}{[1-P(0)-P(1)]}$

                                     $=\frac{(0.20+0.15)}{1-0.20-0.30}$

                                     $=\frac{0.35}{0.5}$

                                     $=0.70$