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rusak2 [61]
4 years ago
11

the plot of land availiable for the mall buliding is a rectangle with an area of 840,736 ft to j2nd power .The width of the lot

of land is 208 ft.if the mall will cover the entire plot of land how long will it be
Mathematics
1 answer:
algol [13]4 years ago
6 0

Please write this as "840,736 ft^2."

Area = length times width. If the width is given, then the length is Area / length.

Here, that's


840736 ft^2

length = ------------------- = 4042 ft

208 ft

The mall will be 4,042 feet long.

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What is 4.22 x 10^17 seconds
Allushta [10]

We can rewrite the given time as:

  • 7.03x10^15 mins
  • 1.17x10^14 hours.
  • 4.88x10^12 days.
<h3>What is 4.22x10^17 seconds in minutes and hours?</h3>

First, remember that:

60s = 1 min

Then to write that amount in minutes, we just need to divide by 60, so we get:

(4.22x10^17)/60  mins=  7.03x10^15 mins

Now, remember that:

1 hour = 3600s

Then to get the time in hours, we need to divide by 3600:

(4.22x10^17)/3600 h = 1.17x10^14 hours.

Similarly, you can change to any time unit that you want, for example:

1 day = 24*3600 s

Then the time in days is:

(4.22x10^17)/(24*3600) days = 4.88x10^12 days.

And so on.

If you want to learn more about changes of units:

brainly.com/question/9032119

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8 0
1 year ago
a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the
kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Step-by-step explanation:

The population growth can be modeled as an exponential function,

P(t) = P_0e^{rt}

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

P(t) = 45e^{0.22t}

Assuming that the starting year is 2020,

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

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3 years ago
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kirill115 [55]
11/3*6/11=66/33=2
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3 years ago
Buchtal, a manufacturer of ceramic tiles, reports on average 2.3 job-related accidents per year. Accident categories include tri
Marianna [84]

Answereippcb.jrc.ec.europa.eu

Step-by-step explanation:

this I the wed go on it and you will get your answer

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3 years ago
15% of the students in the library have brown eyes. If there are 9 students with brown eyes, How many students are in the librar
kirill [66]

Answer:

Step-by-step explanation:

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3 years ago
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