Question

PLEASE HELP ASAP!!!

Answer 1

Answer:

1: x^2-4x+5

2: -x^2-2x+3

3: x^2-6x+5

Step-by-step explanation:

Since these are quite simple parabolas, you can just look at the y-intercept of each equation to determine which one matches up.

Answer 2

Answer:

f(x)=$-x^2-2x+3$-Garph II

f(x)=$x^2-4x+5$-Graph I

f(x)=$x^2-6x+5$-Graph III

Step-by-step explanation:

We are given that

f(x)=$-x^2+2x-3$

If substitute x=0 then we get f(0)=-3

It means y- intercept =-3

In given graph , there is no y- intercept=-3

It is false.

f(x)=$-x^2-2x+3$

If substitute x=0 the we get

f(0)=3

In second graph y - intercept =3

Substitute x=-1 then we get

f(-1)=-1+2+3=4

Hence, the function match with second graph.

f(x)=$x^2-4x+5$

If x=0 then we get

y- intercept =5

If we substitute x=2 then we get

f(1)=4-8+5=1

Hence, function match with First graph.

In third graph

Y- intercept =5

The vertices of parabola is (3,-4)

f(x)=$x^2-6x+5$

If substitute x=0 then we get

y intercept =5

If we substitute x=3

Then we get

f(3)=$3^2-6(3)+5$

f(3)=9-18+5=-4

Hence, the function match with third graph.