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Vika [28.1K]
3 years ago
13

The function f(x) = 2 • 5x can be used to represent the curve through the points (1, 10), (2, 50), and (3, 250). What is the mul

tiplicative rate of change of the function?
Mathematics
1 answer:
Oksana_A [137]3 years ago
7 0
For this case we have a function of the form:
 f (x) = 2 * 5 ^ x

 We will evaluate the function for different values of x:

 For x = 1:
 
f (1) = 2 * 5 ^ 1 = 2 * 5 = 10


 For x = 2:
 
f (2) = 2 * 5 ^ 2 = 2 * 25 = 50


 For x = 3:
 
f (3) = 2 * 5 ^ 3 = 2 * 125 = 250


 We note that for each value of x, the function is 5 times greater than the previous value.
 
 Answer:
 
The multiplicative rate of change of the function is:
 
5
 
The function is 5 times greater for each value of x.
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35 + 115 + 30 = 180 degrees

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3 years ago
Jennifer drew one point at -3 on a number line, and another point at the opposite of -3 how far apart are Jennifer’s 2 points on
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4 0
2 years ago
What is 5C3?<br> A. 35<br> B. 10<br> C. 14<br> D. 28
galben [10]

Answer: B. 10

-5C3 or 5 choose 3 refers to how many combinations are possible from 5 items, taken 3 at a time. To calculate combinations, we will use the formula nCr = n! / r! ... * (n - r)!, where n represents the total number of items, and r represents the number of items being chosen at a time.

-10 is the total number of all possible combinations for choosing 3 elements at a time from 5 distinct elements without considering the order of elements in statistics & probability surveys or experiments. The number of combinations for sample space 5 CHOOSE 3 can also be written as 5C3 in the format of nCr or nCk.

Step-by-step explanation: Hope this help :D

5 0
2 years ago
Read 2 more answers
3 octagons 4 Pentagons 2 trapezoids how many sides are on the shapes altogether
klio [65]

Answer:

52 Sides

Step-by-step explanation:

Octagons have 8 sides so 3 x 8 = 24

Pentagons have 5 sides so 4 x 5 = 20

Trapezoids have 4 sides so 2 x 4 = 8

Add it all up and it equals 52 sides in total

8 0
3 years ago
Find the number of elements in A1 ∪A2 ∪A3 if there are 100 elements in A1, 1000 in A2, and 10,000 in A3 if a) A1 ⊆ A2 and A2 ⊆ A
Stella [2.4K]

Answer:

Step-by-step explanation:

Given that there are 3 sets such that  there are 100 elements in A1, 1000 in A2, and 10,000 in A3

a) If A1 ⊆ A2 and A2 ⊆ A3

then union will contain the same number of elements as that of A3

i.e. n(A1 ∪A2 ∪A3)=n(A3) =10000

b) If the sets are pairwise disjoint.

union will contain the sum of elements of each set

n(A1 ∪A2 ∪A3) = 100+1000+10000=11100

c) If there are two elements common to each pair of sets and one element in all three sets

We subtract common elements pairwise and add common element in 3

i.e. n(A1 ∪A2 ∪A3) = 100+1000+10000-2-2-2+1\\= 10995

5 0
3 years ago
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