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Lady bird [3.3K]
3 years ago
13

(dads age:  28 years old   when  cindys age : 2 years old .)

Mathematics
1 answer:
Delicious77 [7]3 years ago
4 0
So dad=28
cindy=2
so 28-2=diffirance in age=26

A.  dad-26=cindy
      cindy=dad-26
      dad=cindy+26
    so since cindy=18
dad=18+26=44

B. if dad =42=cindy+26 so 
42=x+26
subtract 26 from both sides
16=x
cindy =16 if dad =42

C. so the number of years apart they will be will always be 26 (until one of them dies)
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Please help! geometry problem 3!
Vilka [71]
Comment
|First of all, the triangles are equal by ASA the way the diagram has been marked.

B and E are both right angles.
Side BC = Side DE
<BCA =< EDA 

So triangle BCA = triangle EDA

Now to the letters.
x = y - 1                 Add 1 to both sides.
x + 1 = y                (1)
3x - 2 = 2y + 1       Subtract 1 from both sides.
3x -2 - 1 = 2y
3x - 3 = 2y             Divide by 2
3x/2 - 3/2 = 2y/2
1.5x - 1.5 = y    (2)

Step One
Since (1) and (2) both have y isolated on their respective right sides, they can be equated.

1.5x - 1.5 = x + 1       Take an x from both sides.
0.5x - 1.5 = x - x + 1
0.5x - 1.5 = 1           Add  1.5 to both sides.
0.5x =  1 + 1.5
0.5x = 2.5                 Divide 0.5 on both sides.
0.5x/0.5 = 2.5/0.5

x = 5

Now we need a y value.
x = y - 1 
5 = y - 1 Add 1 to both sides.
5 + 1 = y - 1 + 1
6 = y 

So the 2 sides and the 2 angles are equal when 
x = 5
y = 6

C Answer <<<<<<



 


4 0
3 years ago
Can anyone answer number 9? You have to write the equation and solve.....
hodyreva [135]
(1/2)n+5=9
(1/2)n=4
n=8.
8 0
3 years ago
Use the ordinary division of polynomials to find the quotient and remainder when the first polynomial is divided by the second.
Vanyuwa [196]

The quotient and remainder when the first polynomial is divided by the second are -4w^2 - 7w - 21 and -71 respectively

<h3>How to determine the quotient and remainder when the first polynomial is divided by the second?</h3>

The polynomials are given as:

-4w^3 + 5w^2 - 8, w - 3

Set the divisor to 0.

So, we have

w - 3 = 0

Add 3 to both sides

w = 3

Substitute w = 3 in -4w^3 + 5w^2 - 8 to determine the remainder

-4(3)^3 + 5(3)^2 - 8

Evaluate the expression

-71

This means that the remainder when -4w^3 + 5w^2 - 8 is divided by w - 3 is -71

The quotient (Q) is calculated as follows:

Q = [-4w^3 + 5w^2 - 8]/[w - 3]

The numerator can be expressed as follows:

Numerator = -4w^3 + 5w^2 - 8

Subtract the remainder.

So, we have:

Numerator = -4w^3 + 5w^2 - 8 + 71

This gives

Numerator = -4w^3 + 5w^2 + 61

So, the quotient becomes

Q = [-4w^3 + 5w^2 + 61]/[w - 3]

Expand

Q = [(w - 3)(-4w^2 - 7w - 21)]/[w - 3]

Evaluate

Q = -4w^2 - 7w - 21

Hence, the quotient and remainder when the first polynomial is divided by the second are -4w^2 - 7w - 21 and -71 respectively

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

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The answer is 2 y= 2 so 3•2=6 6-4=2
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