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3 years ago

Lots of points.

Mathematics

1 answer:

Kazeer [188]3 years ago

3 0

Answer:

1. Not a function.

2. This is a function.

3. This is a function.

Step-by-step explanation:

1. 13 maps on to 4 and -4 so not a function.

2 and 3 - these both pass the vertical line test so they are functions.

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I need help with the question attached. Please help me!

Elis [28]

The answer would be C) The volume is the same in both cylinders

8 0

3 years ago

The area of a rectangle is 20 square inches. If the length is 4 inches less than 6 times the width, then find the dimensions of

Tpy6a [65]

Step-by-step explanation:

Let the width=x

Length =6x-4

As we know that in a rectangle

${\boxed{\sf Area=LB}}$

Substitute the values

$\hookrightarrow\sf x (6x-4)=20$

$\hookrightarrow\sf 6x^2-4x=20$

$\hookrightarrow\sf 6x^2-4x-20=0$

Here a=6, b=-4, c=-20.
use quadratic formula

$\hookrightarrow\sf x=\dfrac {1}{3}+\dfrac {1}{3}\sqrt {31} \quad or \quad \dfrac {1}{3}+\dfrac {-1}{3}\sqrt {31}$

8 0

3 years ago

Line m is parallel to line n.If the slope of line m is -2,what is the slope of line n?

Akimi4 [234]

Answer:

-2

Step-by-step explanation:

they are parallel so same slope but different y intercepts

5 0

3 years ago

Negative 11/14 times negative (1/17)

JulijaS [17]

Step-by-step explanation:

$- \frac{11}{14} \times - \frac{1}{17} \\ = \frac{11}{14 \times 17} \\ = \frac{11}{238}$

Hope it will help :)

7 0

3 years ago

Read 2 more answers

Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a

Natasha_Volkova [10]

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.95$ . So we have T = 2.064

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.064\frac{10.2}{\sqrt{25}} = 4.21$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

6 0

3 years ago