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2 years ago

-2log5 7x=2 the 5 is small please help me

1 answer:

3 0

-2log_5 7x = log_5 2

log_5[1/(7x)^2] = log_5 2

log_5(1/49x^2) = log_5 2

log_5(1 - 49x^2) = log_5 2

1 - 49x^2 = 2

You finish.

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ava had 30 dollars. she spent half of what she had at the friday night football game and then earned 8 dollars babysitting. how

Tresset [83]

30/2+8

30/2=15

15+8=23

she finished with $23

5 0

2 years ago

Read 2 more answers

HEEEEEEEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLP please

djverab [1.8K]

Answer:

Step-by-step explanation:

The y-intercept is 2 and the slope is 1. Therefore, the answer is 2y=x. :)

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2 years ago

Find AB, given that line AD is the perpendicular bisector of BC

astraxan [27]

Answer:

AB = 9

Step-by-step explanation:

The perpendicular bisector divides Δ ABC into 2 congruent triangles, that is

Δ ABD ≅ Δ ACD , then

AB = AC = 9

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2 years ago

Left Witch needs 3.25 gallons of "Toe of Frog" in her potion. If she can get half a gallon for $2.50, how much will she spend

Sladkaya [172]

Answer:

$16.25

Step-by-step explanation:

Half a gallon for $2.50 is the same as a quarter a gallon for $1.25.

If she needs 3.25 gallons, which is 13 quarters, we do $1.25 * 13 = $16.25.

Therefore, she will spend $16.25.

6 0

1 year ago

Oh no! Thomas is lost in the GGBL building after an exam, and trying to get out. Thereare four identical hallways leading away f

Brums [2.3K]

Answer:

Check the explanation

Step-by-step explanation:

Since each and every one of the 4 hallways is equally likely then

$P(H1)=1/4P(H2)=1/2P(H3)=1/4$

Now, if he chooses H1 he escapes after 12 minutes then

$E(T|H1)=12$

If he chooses H2 then he wastes 10 minutes and then he is again in the same starting

position so he expects to escape in E(T) minutes, then

$E(T|H2)=10+E(T)$

Analogously, if he chooses H3 then he wastes 40 minutes and then he is again in the same starting

position so he expects to escape in E(T) minutes, then

$E(T|H3)=40+E(T)$

Therefore

$E(T) = E(T|H1)P(H1) + E(T|H2)P(H2) + E(T H3)P(H3) = (12) + (E(T) +10) + (E(T) + 40) = 3+ *E(T)+5+ 10 = E(T) +18 CON A'$

So we have

$E(T) = E(T) + 18 E(T) = 18 E(T) = 4(18) = 72$

Therefore he is expected to escape in 72 minutes

7 0

2 years ago