is a polynomial and thus continuous everywhere and differentiable on any open interval. (second option)
The MVT then guarantees the existence of 
such that
We have
so
Answer:
It’s not c on Plato
Step-by-step explanation:
We have two equation with two unknowns. Therefore, we can solve the x and y easily. There are a number of methods to apply here but I will be using substitution method. We do as follows:
-2x + y = 1
y = 1 + 2x
4x + y = -1
4x + 1 + 2x = -1
6x = -1 -1
6x = -2
x = -1/3
y= 1 + 2(-1/3)
y = 1/3
