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melomori [17]
3 years ago
11

In whole milk, 13 parts out of 400 are milk fat. In 2% milk, 1 part out of 50 is milk fat. Which type of milk has more milk fat

per cup?
Mathematics
1 answer:
Basile [38]3 years ago
5 0
The best thing to do is to make sure that they're equal, and you should multiply 50 to get 400, rather than dividing 400 to get 50.
400/50= 8.
Therefore, you've got to multiply the 2% fat by 8, 1x8= 8, 50x8=400.
Therefore, the 2% fat has 8 parts milk,
Meaning that the whole milk has more days per part.
Hope this helps :)
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An airplane flies from City A in a straight line to City B, which is 120 kilometers north and 180 kilometers west of City A. How
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Answer: 216 kilometers

Step-by-step explanation:

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so...

√(120^2 + 180^2)

√(14400 + 32400)

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216.33

5 0
3 years ago
What is the sum of the measures of the interior angles of a regular polygon if leach exterior angle measures 120°?
GREYUIT [131]

Answer:

180

Step-by-step explanation:

180-120 = 60 this is one of all the congruent angles

of the top of my head i know a regular triangle has three 60 degree angles meaning it is 60*3 = 180

5 0
3 years ago
Find the derivative of g(y)=(y-4)*(2y+y^2)
sasho [114]

Answer:

g'(y)=3y^2-4y-8

Step-by-step explanation:

start by foiling out the given function

g(y)=(y-4)(2y+y^2)\\=2y^2+y^3-8y-4y^2\\=y^3-2y^2-8y

next, use the power rule to find the derivative

power rule: To use the power rule, multiply the variable's exponent n, by its coefficient a, then subtract 1 from the exponent. If there's no coefficient (the coefficient is 1), then the exponent will become the new coefficient.

g'(y)=3y^2-4y-8

5 0
1 year ago
PLEASE HELP NEED DONE ASAP !! I WILL REWARD BRAINLIEST
strojnjashka [21]
39,916,800 is the answer
4 0
4 years ago
Find the equation of the line that is perpendicular to 3y-x=7 and passes through the point (2,-1
boyakko [2]
Hello
<span>an equation for the line in​ point-slope form and general form is :
y = ax+b   a : </span>slope  ; the <span>Passing through (x' ; y')
</span>y' = ax'+b 
y-y' =a(x-x')      and : x' =2   y' = - 1
calculate a :
let :  y = ax+b .....(D)
   ....<span>3y-x=7</span>....(D') or  y = (1/3)x+7/3
.(D) perpendicular to(D') : slope (D) × slope (D') = -1 

 slope (D') = 1/3
slop(D)×(1/3) = -1
slope (D) = -3
equation for the line    :   y-y' =a(x-x') 
y+1 =(-3) (x-2)
7 0
4 years ago
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