Answer:
L(t) = 5·sin(πt) +7
Step-by-step explanation:
The middle of the oscillation of the given function occurs when t=0. At that point, ...
L(0) = d = 7
The next maximum of the oscillation occurs when the argument of the sine function is π/2.
b·t = π/2
b = π/(2t) = π/(2·0.5) = π
At that maximum, the length is 12, so we have ...
L(0.5) = a·sin(0.5π) +7 = 12
a = 5
The function L(t) is ...
L(t) = 5·sin(πt) +7
Answer:the first term is 6
Step-by-step explanation:
We would apply the formula for determining the sum of n terms of an arithmetic sequence. It is expressed as
Sn = n/2(a + l)
Where
n represents the number of terms in the arithmetic sequence.
l represents the last term in the arithmetic sequence.
a represents the first term in the arithmetic sequence.
From the information given,
l = 204
n = 12
Sn = 1260
We want to determine a. Therefore,
1260 = 12/2(a + 204)
1260 = 6(a + 204)
a + 204 = 1260/6 = 210
a = 210 - 204 = 6
Answer:
Step-by-step explanation:
a. 660: 2^2 x 3 x 5 x 11
b. 448: 2^6 x 7
c. 1025: 5^2 x 41
d. 2^2 x 3^2 x 5^2
Answer:
B because the length of R to U is 6x5
Answer:
Step-by-step explanation:
The question is faulty. It works once it gets to + 1, +2, +3
The other x values should be 0 and - 1 instead of -1 and -3.
Here's the formula I get.
f(x) = 2*3^(2x + 1)
f(0) = 2*3^(1)
f(0)= 6
f(-1) = 2*3^(-2 + 1)
f(-1) = 2*3^(-1)
f(-1) = 2/3
f(-2) = 2*3^(-2*2 + 1)
f(-2) = 2*3^(-4 +1)
f(-2) = 2*3^(-3)
f(-2) = 2/27
Since my answers do not agree with the given answers, I can do nothing more to help you. I will pass this along to someone I know who will see through it.