Question

1. If the length of a rectangle is 6 more than its width, and its perimeter is 48

Answer 1

For this case we have that by definition, the perimeter of the rectangle is given by:

$P = 2w + 2L$

Where:

W: Is the width of the rectangle

L: is the length of the rectangle

According to the data we have:

$L = 6 + w\\P = 48$

Substituting:

$48 = 2w + 2 (6 + w)\\48 = 2w + 12 + 2w\\48 = 4w + 12\\48-12 = 4w\\36 = 4w\\w = \frac {36} {4}\\w = 9$

So, the width of the rectangle is 9 inches

$L = 6 + 9 = 15$

So, the length of the rectangle is 15 inches

Answer:

the width of the rectangle is 9 inches

the length of the rectangle is 15 inches