Question

What is the value of n in the equation 1 (n – 4) – 3 = 3 - (2n+3)?

Answer 1

Step-by-step explanation:

$1(n-4)-3=3-(2n+3)$

$n-4-3=3-2n-3\\n+2n=3-3+3+4\\3n=7\\n=\frac{7}{3}$

Proof

$1(n-4)-3=3-(2n+3)$

$1(\frac{7}{3} -4)-3=3-[2(\frac{7}{3}) +3]\\1(\frac{7-12}{3} )-3=3-(\frac{14}{3} +3)\\1(\frac{-5}{3} )-3=3-(\frac{14+9}{3})\\\frac{-5}{3} -3=3-(\frac{23}{3})$

$\frac{-5-9}{3} =\frac{9-23}{3} \\\frac{-14}{3} =\frac{-14}{3}$

Answer 2

Answer:

n=7/3

Step-by-step explanation:

1 (n – 4) – 3 = 3 - (2n+3)

1. distribute the 1 on the left side and distribute the -1 on the right side

1n-4-3=3-2n-3

2. add like terms

1n-7=-2n

3. move n to one side and by itself

-7=-3n

4. divide -3 to get n alone. Both negatives cancel out each other

7/3=n