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just olya [345]

3 years ago

9

Find the y-intercept of the line on the graph

1 answer:

hoa [83]3 years ago

8 0

2 it’s literally just where the line crosses on the y axis

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PLLLLLLZZZZ HELP!! MULTIPLE CHOICE!!

liubo4ka [24]

First, set 2x+7 equal to 3x-7 since they are the same angle due to the parallel lines.

2x+7=3x-7
x=14

Then, since 2x+7 and 12y+1 equals 180, put it together to find y:

(2x+7)+(12y+1)=180
(2(14)+7)+(12y+1)=180
12y+1=145
12y=144
y=12

So, x=14 and y=12. Your answer should be C!

5 0

3 years ago

Write an equation that represents degrees fahrenheit in terms of degrees celsius. let xx represent the temperature in degrees ce

IgorC [24]

As we know Conversion from fahrenheit to celsius is
$F - 32 = \frac{9C}{5}$

We can write it also as

$F = \frac{9C}{5}+32$

F as y and C as x then we can write it as

$y = \frac{9x}{5} + 32$

7 0

3 years ago

1/3 (x - 10) = -4, x <br><br> What is x equal to?

Mrrafil [7]

A n s w e r :

x = - 2

5 0

3 years ago

Read 2 more answers

In which quadrant is sec e< 0 and tan e > 0?

iren2701 [21]

Answer:

C

Step-by-step explanation:

Because Tangent is positive in third quadrant

7 0

3 years ago

A lighthouse is located on a small island 5 km away from the nearest point P on a straight shoreline and its light makes seven r

Vaselesa [24]

Answer:

Light is moving at the speed = 77.78 km/min

Step-by-step explanation:

Given:

Distance between island and point P = 5 km

Moving along the the shoreline when it is 1 km from P.

So, x = 1

From the above statement light makes seven revolutions per minute.

Therefore,

$\frac{d\theta}{dt}=\frac{7\times 2\pi\ rad}{1\ min} = 14\pi\ rad/min$

Solution:

From the given figure.

$tan\theta=\frac{x}{5}$

Substitute x = 1

$tan\theta=\frac{1}{5}$ -------------------(1)

Now, first we differentiate both side with respect to t.

$\frac{d(tan\theta)}{dt} = \frac{d}{dt}.(\frac{x}{3})$

Using chain rule.

$\frac{d(tan\theta)}{dt}.\frac{d\theta}{dt} = (\frac{1}{5})\frac{dx}{dt}$

$sec^{2} \theta.\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}$

$(1+tan^{2} \theta).\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}$

Substitute $tan\theta=\frac{1}{5}$ from equation 1.

$(1+(\frac{1}{3})^{2} ).\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}$

$(1+\frac{1}{9}).\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}$

Substitute $\frac{d\theta}{dt}=14\pi$

$\frac{10}{9}.14\pi = \frac{1}{5}.\frac{dx}{dt}$

Applying cross multiplication rule.

$\frac{dx}{dt}= \frac{700\pi }{9}$

$\frac{dx}{dt}= 77.78\pi$

Therefore, light is moving along the shore at the speed of 77.78 km/min

6 0

3 years ago