Answer:
Infinutely many solutions
Step-by-step explanation:
y = 10x + 2 --------- (1)
y = 8x +2x +2
=> y = 10x + 2---------- (2)
(1) -> 10x -y + 2 = 0
(2) -> 10x -y + 2 = 0
a1=10 ; b1=-1 ; c1 = 2
a2=10 ; b2=-1 ; c2= 2
a1/a2 = 10/10 = 1
b1/b2 = -1/-1 = 1
c1/c2 = 2/2 = 1
therefore, a1/a2 = b1/b2 = c1/c2
Therefore the line coincides and there are infinitely many solutions.
Answer:
A
Step-by-step explanation:
x^2 - 4x +3
(x - 1)(x-3)
x = 1, x = 3
Answer:
Statements Justifications
E bisects AI, BC bisects AE, FH bisects EI Given
AE is congruent to EI Definition of Bisector
AD is congruent to DE Definition of Bisector
EG is congruent to GI Definition of Bisector
If AE is congruent to EI, AD is congruent to DE, and EG is congruent to GI, then AD is congruent to DE, EG, and GI, DE is congruent to AD, EG, and GI, EG is congruent to AD, DE, and GI, and GI is congruent to AD, DE, and EG. Therefore, AD is congruent to EG.
This isn't the best answer and probably won't get you a 100, but it shows effort so...
Answer:
12
Step-by-step explanation:
Since both rectangles are of the same dimensions, simply multiply the width of the first box(2) and the length of the second box(6) together(2*6 = 12)
Solve for
y
y in
5
x
−
y
=
8
5x−y=8.
y
=
5
x
−
8
y=5x−8
2 Substitute
y
=
5
x
−
8
y=5x−8 into
2
0
x
−
4
y
=
2
4
20x−4y=24.
3
2
=
2
4
32=24
3 Since
3
2
=
2
4
32=24 is not true, this is an inconsistent system.
