Let f prime (x) = 2/x and f (square root e) = 5 then f (e) =

1 answer:

7 0

F(x) = 2lnx +c so 5 = 1 +c after substitution.
Means c = 4 and f(x) = (2 lnx) +4 {NOT 2 ln(x+4)}
And so f(e) = 2+4=6.
So 6 is the answer

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