Answer:
The width of the rectangle is 75 meters and length is 480 meters.
Step-by-step explanation:
The perimeter of the rectangle = 1110 meters
Let the width of the rectangle = k meters
So,the length of the rectangle = 6k + 30
Now, PERIMETER OF A RECTANGLE = 2(LENGTH + WIDTH)
⇒ 1110 = 2( k + (6k + 30))
or, 1110 = 14 k + 60
or, 14 k = 1110 - 60 = 1050
⇒ k = 1050/14 = 75
Hence, the width of the rectangle is k = 75 meters
and the Length of the rectangle is 6k + 30 = 6(75) +30
= 480 meters
Answer:
4 days
Step-by-step explanation:
We need to use the probability functions of each of the intervals to know the Probability number and then use it in the expected value.
P(x>3 cargo ships) = 1-P(x<=3)
P(x>3) = 1-P(x<=3)
P(x>3) = 1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)]
![P(x>3) = 1 - [\frac{e^{-2}2^0}{01}+\frac{e^{-2}2^1}{11}+\frac{e^{-2}2^2}{21}+\frac{e^{-3}2^3}{31}]](https://tex.z-dn.net/?f=P%28x%3E3%29%20%3D%201%20-%20%5B%5Cfrac%7Be%5E%7B-2%7D2%5E0%7D%7B01%7D%2B%5Cfrac%7Be%5E%7B-2%7D2%5E1%7D%7B11%7D%2B%5Cfrac%7Be%5E%7B-2%7D2%5E2%7D%7B21%7D%2B%5Cfrac%7Be%5E%7B-3%7D2%5E3%7D%7B31%7D%5D)
P(x>3) = 1- [0.1353(1+2+2+1.33)]
P(x>3) = 1-0.856
P(x>3) = 0.1431
Als n=30, expected number is
E(x) =30*P(x>3)
E(x) = 30*0.1431
E(x) = 4.293
I expect 4.293 or 4 days per month the block being unable to hanlde all arriving ships
Answer:
Step-by-step explanation:
Suppose that at time
we have x mold cells. We are told that after 12 minutes the amount present is double. That is a
we have 2x cells. Then, at
we have (2x)*2 = 4x. We can continue as follows
we have (4x)*2 = 8x.
we have (8x)*2 = 16x
(one hour later) we have (16x)*2 = 32x.
So after one hour from now we have 32x cells.