All categories

3 years ago

Find the area of this whole trapezoid

Mathematics

1 answer:

Julli [10]3 years ago

5 0

Answer:

There isn’t one

Step-by-step explanation:

To answer this you need to find the height

A = ½(b1+b2)h

Since there isn’t a height on the problem it can’t be solved

You might be interested in

I really need help with this and if you don't know it says which one is NOT

Natasha_Volkova [10]

The fourth one I think

3 0

3 years ago

Read 2 more answers

rectangle with a perimeter of 1110 meters, this rectangular shape is 30 meters longer than 6 times its width. find its dimension

Alecsey [184]

Answer:

The width of the rectangle is 75 meters and length is 480 meters.

Step-by-step explanation:

The perimeter of the rectangle = 1110 meters

Let the width of the rectangle = k meters

So,the length of the rectangle = 6k + 30

Now, PERIMETER OF A RECTANGLE = 2(LENGTH + WIDTH)

⇒ 1110 = 2( k + (6k + 30))

or, 1110 = 14 k + 60

or, 14 k = 1110 - 60 = 1050

⇒ k = 1050/14 = 75

Hence, the width of the rectangle is k = 75 meters

and the Length of the rectangle is 6k + 30 = 6(75) +30

= 480 meters

6 0

3 years ago

PLEEEASE HELP ASAP<br> 1. Simplify the following expression:(5*2)*8

adoni [48]

5*2=25

25*8=200

Answer: 200

(Using exponent)

6 0

3 years ago

Read 2 more answers

Cargo ships arrive at a loading dock at a rate of 2 per day. The dock has the capability of handling 3 arrivals per day. How man

Vsevolod [243]

Answer:

4 days

Step-by-step explanation:

We need to use the probability functions of each of the intervals to know the Probability number and then use it in the expected value.

P(x>3 cargo ships) = 1-P(x<=3)

P(x>3) = 1-P(x<=3)

P(x>3) = 1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)]

$P(x>3) = 1 - [\frac{e^{-2}2^0}{01}+\frac{e^{-2}2^1}{11}+\frac{e^{-2}2^2}{21}+\frac{e^{-3}2^3}{31}]$

P(x>3) = 1- [0.1353(1+2+2+1.33)]

P(x>3) = 1-0.856

P(x>3) = 0.1431

Als n=30, expected number is

E(x) =30*P(x>3)

E(x) = 30*0.1431

E(x) = 4.293

I expect 4.293 or 4 days per month the block being unable to hanlde all arriving ships

6 0

3 years ago

The number of mold cells doubles every 12 minutes. At this moment, there are x mold cells present on a piece of bread. Which of

lisabon 2012 [21]

Answer:

Step-by-step explanation:

Suppose that at time $t_0$ we have x mold cells. We are told that after 12 minutes the amount present is double. That is a $t= t_0+12$ we have 2x cells. Then, at $t = t_0+24$ we have (2x)*2 = 4x. We can continue as follows

$t: t_0+36$ we have (4x)*2 = 8x.

$t: t_0+48$ we have (8x)*2 = 16x

$t: t_0+60$ (one hour later) we have (16x)*2 = 32x.

So after one hour from now we have 32x cells.

5 0

4 years ago