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Fantom [35]
4 years ago
6

What is the output when the input is 24.5? A.85.75 B.28 C.49 D.28 E.27.5

Mathematics
2 answers:
alexandr1967 [171]4 years ago
5 0
If you say input and output, I'm assuming that there is a function that you haven't added?
olga55 [171]4 years ago
4 0
It is None of them So be smart thank you
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Consider the following set of equations, where s, s0, x and r have units of length, t has units of time, v has units of velocity
Anna11 [10]

Answer:

5

Step-by-step explanation:

For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.

Also, two physically quantities can only be added or subtracted only when their dimension are same.

here all option are dimensionally correct except the 5th option where

dimension of t= [T] whereas dimension of a/v is \frac{LT^{-2}}{LT^{-1}}

= T^{-1}

since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.

8 0
3 years ago
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
Question is in image attached.
Mama L [17]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
A catering service offers 12 appetizers, 8 main courses, and 4 desserts. A customer is to select 9 appetizers, 3 main courses, a
valentina_108 [34]

Answer:

73920

Step-by-step explanation:

Number of ways to choose 9 appetizers from 12: ₁₂C₉

Number of ways to choose 3 main courses from 8: ₈C₃

Number of ways to choose 2 desserts from 4: ₄C₂

The total number of ways is:

₁₂C₉ × ₈C₃ × ₄C₂

= 220 × 56 × 6

= 73920

5 0
3 years ago
If m XAB=32, what is m BAC?
dalvyx [7]
The picture in the attached figure

we know that
<span>The construction shown is an angle bisector
m<XAB=m<CAX
</span>so
m<BAC=2*[m<XAB]-----> 2*32°----->m<BAC= 64°

the answer is
m<BAC=64°

3 0
4 years ago
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