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weeeeeb [17]
3 years ago
5

Jill is applying for a car loan. which individual will run her credit report to determine if she's eligible for a car loan?

Mathematics
2 answers:
Vitek1552 [10]3 years ago
5 0

a creditor will run her report,

 creditor = credit report.

Allushta [10]3 years ago
4 0

Answer:

a) Creditor

Step-by-step explanation:

a) Right. Creditor

She's applying for a Car loan, the Creditor, i.e. the one who is going to lend her the money to buy a new car. In this case, if Jill is applying to a bank . The creditor will be the Bank she's applying for.

Let's look a the definition of Creditor:

A creditor is a person or company that provides credit to another person or company functions as a creditor.

creditor. (n.d.) Lightbulb Press Dictionary of Financial Terms. (2008). Retrieved September 18, 2019

b) Wrong. There is no direct cause-effect relation since a Government Representative might describe virtually any public civil servant. And also her application has nothing to do with Public Funding.

c) Wrong. Her employer is not the person appointed to determine if she's able to receive the loan. As her boss He/She whether Jill is eligible for a car loan.

d) Wrong. Similarly, her landlord is not the person appointed to determine if she's able to receive the loan.

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\bold{\huge{\underline{ Solution }}}

<u>We </u><u>have</u><u>, </u>

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Let the coordinates of the end point of the line segment AB be ( x1 , y1 ) and (x2 , y2)

<u>Also</u><u>, </u>

Let the coordinates of midpoint of the line segment AB be ( x, y)

<u>We </u><u>know </u><u>that</u><u>, </u>

For finding the midpoints of line segment we use formula :-

\bold{\purple{ M( x,  y) = }}{\bold{\purple{\dfrac{(x1 +x2)}{2}}}}{\bold{\purple{,}}}{\bold{\purple{\dfrac{(y1 + y2)}{2}}}}

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

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<u>For </u><u>x </u><u>coordinates </u><u>:</u><u>-</u>

\sf{  -8  = }{\sf{\dfrac{(- 2 +x2)}{2}}}

\sf{2}{\sf{\times{ -8  = - 2 + x2 }}}

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\bold{ x2 = -14  }

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<u>For </u><u>y </u><u>coordinates </u><u>:</u><u>-</u>

\sf{  8  = }{\sf{\dfrac{(- 20 +x2)}{2}}}

\sf{2}{\sf{\times{ 8   = - 20 + x2 }}}

\sf{ 16 = - 20 + x2 }

\sf{ y2 = 16 + 20 }

\bold{ y2 = 36  }

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Hence, Option A is correct answer

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