3 years ago

does this inequality sometimes, always, or never true for any value of the variable. 12s. > 10s

1 answer:

6 0

If you take away the S variable, the inequality is
12>10
Since 10 will always be less than 12 the answer is:
The inequality is always true for any value of the variable

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What are the restrictions for y <br> X=10/5+y

Naya [18.7K]

Answer:

$y\ne-5$

Step-by-step explanation:

So you have the equation:

$x=\frac{10}{5+y}$ . As you may know, you cannot divide by 0, so y has to be restricted in a way that the denominator is never equal to 0. So to find when y makes the denominator 0, simply set the denominator equal to 0, and solve for y. This gives you the equation: 5+y = 0, y=-5. So the y value CANNOT be equal to -5. Because it makes the denominator 0. so $y\ne-5$ would be the restriction.