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lesya692 [45]
3 years ago
10

does this inequality sometimes, always, or never true for any value of the variable. 12s. > 10s

Mathematics
1 answer:
Vadim26 [7]3 years ago
6 0
If you take away the S variable, the inequality is
12>10
Since 10 will always be less than 12 the answer is:
The inequality is always true for any value of the variable
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Please helppp
tangare [24]

Answer:

Adult: 50 tickets

Child: 34 tickets

Step-by-step explanation:

Let a be the amount of adult tickets

Let c be the amount of child tickets

Equation:

a + c = 84

14a + 9c = 1,006

Step 1: Multiply a + c = 84 with -9, to canceled c.

-9 (a + c = 84)    →  -9a - 9c = -756

14a + 9c = 1006 → 14a + 9c = 1006

Step 2: Combined the 2 equation together, and solved it.

-9a - 9c = -756

<u>14a + 9c = 1006</u>

       <u> 5a</u> = <u>250</u>

        5        5

           a = 50

Step 3: Plug 50 into the one of the equation, and solved it.

a + c = 84 → 50 + c = 84

                  <u>-50         -50</u>

                            c = 34

Answer: Adult tickets (a) = 50 and Child tickets (c) = 34

To check the answer plug the two number into the equation ( Make sure to add 50 for a and 34 for c).

3 0
3 years ago
richard spends 30% of his monthly budget on rent. His total monthly is 3,000. How much does Ricard spend on rent
Alexeev081 [22]
He spends 900 on rent
6 0
3 years ago
Read 2 more answers
What is the probability of rolling a dice at most 3 times until a 6 occurs
IRISSAK [1]

Answer:

Probablity of getting six in at most three roll= 0.199.

Step-by-step explanation:

Given: Dice rolled at most 3 times untill a 6 occurs.

First, finding the probablity of getting 6 in a dice if rolled once.

Probablity= \frac{chances\ of\ occurance}{Total\ number\ of\ event}

We know, dice have six side, therefore, total number of event will be 6.

∴ Probablity of getting six in one roll= \frac{1}{6}

As given, Dice is rolled at most 3 times.

Now, finding the probablity of getting 6 in a dice if rolled 3 times.

∴ Probablity of getting six in three roll= \frac{1}{6}+(\frac{1}{6})^{2} +(\frac{1}{6})^{3}

⇒ Probablity of getting six in three roll=  \frac{1}{6}+\frac{1}{36} +\frac{1}{216}

Taking LCD 216

⇒Probablity of getting six in three roll= \frac{1\times 36+ 6\times 1+1}{216}

⇒Probablity of getting six in three roll= \frac{43}{216}

∴Probablity of getting six in three roll=0.199

           

3 0
4 years ago
Can yall pls help with this
Blizzard [7]

Answer:

x=7

Step-by-step explanation:

3 0
3 years ago
Tough Math Help !
arsen [322]
Put 4 months over 12 months. Reduce to 1/3.

i=prt
i=300(0.9)(1/3)
i=$90
4 0
3 years ago
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