The answer is: switches.
Explanation:
Filtering is a function of switches.
Answer:
myInt=40
myFloat=4.8
Explanation:
First look at the function definition .It has two arguments intVal is passed by reference while floatVal is passed by value.So the changes done on the myInt variable will be reflected on the original argument because when a variable is passed by reference the the changes are reflected on the original argument but when a variable is passed by value the function created a duplicate copy of it and work on them so changes are not reflected on the original argument.So myInt will get doubled while myFloat will remain the same.
Answer:
import java.util.Scanner;
public class num4 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int sumOdds =0;
int sumEvens =0;
int num;
do{
System.out.println("Enter positive integers");
num = in.nextInt();
if(num%2==0){
sumEvens+=num;
}
else if (num%2!=0){
sumOdds+=num;
}
}while (num>0);
System.out.println("The sum of evens: "+sumEvens);
System.out.println("The sum of odds: "+sumOdds);
}
}
Explanation:
- Import Scanner class to prompt and receive user input
- Declare the following variables and initialize them int sumOdds =0, int sumEvens =0, int num;
- Create a do....while loop That continously prompts user to enter a positive number. The loop should terminate when a negative number is enters (n<=0)
- Within the while loop use an if condition with the modulo (%) operator to determine even and odd numbers and add to the respective variables
- Outside of the while loop Print sum of odds and sum of evens
Answer: type the label in A1 and use autofill
Explanation:
Took the final 2021 Edgeunity
