2 years ago

Put a check by all the factors of 20.

Mathematics

1 answer:

Degger [83]2 years ago

3 0

1,2,4,5,10,20 are all factors of 20. (To be extra sure you can ask google too).

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<img src="https://tex.z-dn.net/?f=108cm%20%7B%3F%7D%5E%7B2%7D%20" id="TexFormula1" title="108cm {?}^{2} " alt="108cm {?}^{2} " a

scoundrel [369]

A(base)=6*6=36
A( triangle)=1/2*(base of the triangle)*height( of the triangle)=1/2*6*4=12
one base +4 triangles=36+4*12=36+48 =84 cm²

8 0

2 years ago

Is 23 and 25 co-primes

MariettaO [177]

Answer:

yes because they have one as a company factor

7 0

3 years ago

A student made a list of questions to gather data about a local movie theater. She will ask a sample of her classmates to answer

Wewaii [24]

Answer: A D E

Step-by-step explanation:

3 0

2 years ago

47. What is the 12th term of the geometric sequence?

GrogVix [38]

Answer:

Step-by-step explanation:

The rule is 2x.

So 3,6,12,24,48,96,192,384,768,1536,3072,6144,12288,....

The question asked for the 12th term so 6144.

5 0

2 years ago

Read 2 more answers

Zander read 13 3/4pages in 1/4 of an hour. Sydney read 43 1/3 pages in 2/3 of an hour. At these rates, would Zander or Sydney re

kakasveta [241]

Answer:

At these rates Sydney read 10 pages per hour more than Zander.

Step-by-step explanation:

Zander read $13\frac{3}{4}$ pages in $\frac{1}{4}$ of an hour.

Therefore, pages read by Zander in 1 hour = $\frac{\text{Total pages read}}{\text{Total time taken}}$

= $\frac{13\frac{3}{4}}{\frac{1}{4}}$

= $\frac{55}{4}\times \frac{4}{1}$

= 55 pages per hour

Sydney read $43\frac{1}{3}$ pages in $\frac{2}{3}$ of an hours.

Pages read by Sydney in 1 hour = $\frac{43\frac{1}{3}}{\frac{2}{3} }$

= $\frac{130}{3}\times \frac{3}{2}$

= 65 pages per hour

Therefore, number of pages read more by Sydney as compared to Zander,

= 65 - 55

= 10 pages per hour

At these rates Sydney read 10 pages per hour more than Zander.

4 0

2 years ago