Solve for j -1/3=j/4-10/3
1 answer:
You might be interested in
<h3>Answer: Check out the screenshots below.</h3>
=========================================
Explanations:
Part 1
For the first box, we use the log rule that log(A)+log(B) = log(A*B)
Then in the second box, we'll convert to exponential form. The logs are assumed to be base 10.
The third box then factors and uses the zero product property.
----------------------------
Part 2
We check each solution generated in part 1.
Plugging x = 5/3 will lead to the same number on each side. Therefore, x = 5/3 is a true solution.
In contrast, plugging x = -2 leads to a false equation. Recall that the domain of y = log(x) is x > 0. This means we cannot replace x with negative numbers. The value x = -2 is extraneous.
----------------------------
Part 3
There's not much to explain here that isn't already done so on the screenshot below.