Which of the following is not a solution to the system of linear equations below?

Write an equation (a) in slope-intercept form and (b) in standard form for the line passing through (-3,5) and parallel to x + 4

Dmitry [639]

Answer:

$\boxed{\sf Standard-form :x + 4y -17=0 }\\$

$\boxed{\sf Slope-intercept\ form :y =\dfrac{-1}{4}x +\dfrac{17}{4}}$

Step-by-step explanation:

Here a equation of the line is given to us and we need to find out the equation of line which passes through the given point and parallel to the given line , the given equation is ,

$\longrightarrow x + 4y = 7\\$

Firstly convert it into slope intercept form of the line which is y = mx + x , as ;

$\longrightarrow 4y = -x + 7 \\$

$\longrightarrow y =\dfrac{-x}{4}+\dfrac{7}{4}\\$

On comparing it to y = mx + c , we have ,

$\longrightarrow m =\dfrac{-1}{4}\\$

$\longrightarrow c =\dfrac{7}{4}\\$

Now as we know that the slope of two parallel lines is same . Therefore the slope of the parallel line will be ,

$\longrightarrow m_{||)}=\dfrac{-1}{4}\\$

Now we may use point slope form of the line as ,

$\longrightarrow y - y_1 = m(x-x_1) \\$

On substituting the respective values ,

$\longrightarrow y - 5 =\dfrac{-1}{4}\{ x -(-3)\}\\$

$\longrightarrow y -5=\dfrac{-1}{4}(x+3)\\$

$\longrightarrow 4(y -5 ) =-1(x +3) \\$

$\longrightarrow 4y -20 = - x -3 \\$

$\longrightarrow x + 4y -20+3=0\\$

$\longrightarrow \underset{Standard \ Form }{\underbrace{\underline{\underline{ x + 4y -17=0}}}} \\$

Again the equation can be rewritten as ,

$\longrightarrow y - 5 = \dfrac{-1}{4}(x +3) \\$

$\longrightarrow y = \dfrac{-1}{4}x -\dfrac{3}{4}+5 \\$

$\longrightarrow y = \dfrac{-1}{4}x -\dfrac{20-3}{4} \\$

$\longrightarrow \underset{Slope-Intercept\ form }{\underbrace{\underline{\underline{ y =\dfrac{-1}{4}x +\dfrac{17}{4}}}}}\\$

6 0

2 years ago

Round to nearest tenth

Goshia [24]

Answer:

Step-by-step explanation:

this is exactly the same as the 1st one, just they put it in a different orientation. sooo use law of cosines , where

QR = c

a = 12

b = 23

cos(120) = cos (P)

c = sq rt [ a^2+b^2﹣2*a*b*cos(P) ]

QR = sq rt [ 12^2 + 23^2 - 2* 12*23*cos(120) ]

QR = sq rt [ 144 + 529 - 552 * (-0.5 0 ]

QR = sq rt [ 673 + 276 ]

QR = sq rt [ 949 ]

QR = 30.8058

rounded to nearest 10th is

QR = 30.8 :)

6 0

3 years ago

Store a sells 12 bottles of water for 3.36 store b sells 24 bottles of water for 6.00 How much more Willa customer pay for 48 bo

Nataly_w [17]

Answer:

$1.44

Step-by-step explanation:

Store A:

12 bottles of water for $3.36

Then

48 bottles of water for $\$3.36\cdot 4=\$13.44$ (48 bottles is 4 times greater than 12 bottles)

Store B:

24 bottles of water for $6.00

Then

48 bottles of water for $\$6.00\cdot 2=\$12$ (48 bottles is twice greater than 24 bottles)

Difference:

$\$13.44-\$12=\$1.44$

6 0

3 years ago

S

Novay_Z [31]

Step-by-step explanation:

s is inversely proportional to t

If s= 0.6 , t= 4

s=k/t

0.6= k/4

k=2.4

If s=12, then

t=k/s

t=2.4/12

t=0.05

8 0

2 years ago

In scoole i need to know whats 14.6 divided by 2

ICE Princess25 [194]

The answer is 7.3. Hope that helps.

8 0

3 years ago

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