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coldgirl [10]
4 years ago
12

Point E is between points D and F. If DE= x-4, EF= 2x+5, and DF= 4x-8, find x.

Mathematics
2 answers:
Luda [366]4 years ago
8 0
DE= x-4 
EF = 2x+5
DF = 4x-8

now,  <span>Point E is between points D and F
</span>
so, DF = DE + EF

4x-8 = (x-4) + (2x+5)  \\&#10;4x-8 = 3x +1  \\&#10;x = 9
blsea [12.9K]4 years ago
6 0

Answer:

Step-by-step explanation:

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The equation of circle having a diameter with endpoints (-3, 1) and (5, 7) is
nydimaria [60]
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(x-h)^2+(y-k)^2=r^2
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r=\sqrt{(x_1-h)^2+(y_1-k)^2}=\sqrt{(-3-1)^2+(1-4)^2}=\\&#10;=\sqrt{(-4)^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5 \\ \Downarrow \\&#10;r^2=5^2=25

The equation of the circle:
\boxed{(x-1)^2+(y-4)^2=25}
8 0
3 years ago
Read 2 more answers
Area of Composite Figures
AlekseyPX

Answer:

1) 147

2) 87m^{2}  

Step-by-step explanation:

1) Area of triangle = × base length × height

= \frac{1}{2} × 14 × 10

= 70 m^{2}

Area of a semicircle = \frac{\pi r^{2} }{2} ( r is the radius)

Radius = half of diameter = \frac{14}{2} = 7m

Area of semicircle = \frac{\pi 7^{2} }{2} = \frac{\pi49 }{2}

= 77m^{2} ( Nearest whole number )

Total area = 77 + 70 = 147m^{2}

2) Divide the shape into 2 rectangles

Area of a rectangle = length × width

Rectangle 1 = 7 × ( 3+3+5 )

= 7 × 11 = 77m^{2}

Rectangle 2 = 2 × 5

= 10m^{2}

Total Area = 77 + 10 = 87m^{2}

8 0
3 years ago
Read 2 more answers
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