Answer:
someone is adding dont worrie
Step-by-step explanation:
9514 1404 393
Answer:
Step-by-step explanation:
In the left problem, you use the fact that <em>the sum of the segment lengths is equal to the overall length</em>.
AC +CB = AB
(3x -4) +(x -2) = 62
4x -6 = 62 . . . . . collect terms
4x = 68 . . . . . . . add 6
x = 17 . . . . . . . . . . divide by 4
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In the right problem, you use the fact that <em>the sum of the angles is equal to the overall angle</em>. Here, that overall angle is a linear angle, so measures 180°.
∠DFG +∠GFE = ∠DFE
(5y +3) +(2y -5) = 180
7y = 182 . . . . . . . . . . . . . . collect terms, add 2
y = 26 . . . . . . . . . . . . . . . .divide by 7
Let us find the co ordinates of each vertex of the triangle .
Vertex A ( in firs second quadrant) = ( -5 ,3)
vertex B in third quadrant = ( -5, -5)
vertex C in fourth quadrant = ( 4, -2)
let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0
AB= 8
BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90
BC = 9.48
AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106
AC= 10.29
Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77
<span>-5 > -4 FALSE
-8 > -9 TRUE
5 < 4 </span>FALSE<span>
-8 > 5 </span>FALSE
answer
-8 > -9
To find the area of all of the figures, all you need to do is base x height or the length x width.
Your answers for 1-6 are all correct.
For 7-9, remember that the area is the length times the width.
7) length x width, 42 x 30=1260
8) 17 x 22= 374
9) Since the length and width are the same in a square just multiply the side by itself. 2.7 x 2.7= 7.29
Hope this helps.
