Answer:
Step-by-step explanation:
it is important because if you don't then you will be charged more than what you are supposed to pay
Answer:
1. 8.85 quarts
2. 44.25%
Step-by-step explanation:
In 15 quarts of a solution with percentage of antifreeze = 35%
Amount of antifreeze = 35% × 15
= 0.35 × 15
= 5.25 quarts
that solution is mixed with 5 quarts of a solution with percentage of antifreeze = 72%
Amount of antifreeze = 72% × 5
= 0.72 × 5
= 3.6 quarts
Total amount of mixture = 15 quarts + 5 quarts = 20 quarts
1. Now we will calculate the total amount of antifreeze in the resulting mixture.
= 5.25 + 3.6 = 8.85 quarts
2. The percentage of the resulting mixture is antifreeze
= ![\frac{8.85}{20}\times 100](https://tex.z-dn.net/?f=%5Cfrac%7B8.85%7D%7B20%7D%5Ctimes%20100)
= 44.25%
1. total amount of antifreeze is 8.85 quarts
2. the percentage of antifreeze is 44.25%
Answer:
-3
Step-by-step explanation:
Simplifying
4(4m + -3) + -1(m + -5) = -52
Reorder the terms:
4(-3 + 4m) + -1(m + -5) = -52
(-3 * 4 + 4m * 4) + -1(m + -5) = -52
(-12 + 16m) + -1(m + -5) = -52
Reorder the terms:
-12 + 16m + -1(-5 + m) = -52
-12 + 16m + (-5 * -1 + m * -1) = -52
-12 + 16m + (5 + -1m) = -52
Reorder the terms:
-12 + 5 + 16m + -1m = -52
Combine like terms: -12 + 5 = -7
-7 + 16m + -1m = -52
Combine like terms: 16m + -1m = 15m
-7 + 15m = -52
Solving
-7 + 15m = -52
Solving for variable 'm'.
Move all terms containing m to the left, all other terms to the right.
Add '7' to each side of the equation.
-7 + 7 + 15m = -52 + 7
Combine like terms: -7 + 7 = 0
0 + 15m = -52 + 7
15m = -52 + 7
Combine like terms: -52 + 7 = -45
15m = -45
Divide each side by '15'.
m = -3
Simplifying
m = -3
Hope this helped :)
$0.30x=y should be the answer because there is a 30cent fee for every day and x represents how many days it's kept therefore you would add 30 cents for every day it's kept so it's valid to say $0.30x=y becaue the 30 cents times the total of days it's kept = y (the toatl)
Answer:
{1, (-1±√17)/2}
Step-by-step explanation:
There are formulas for the real and/or complex roots of a cubic, but they are so complicated that they are rarely used. Instead, various other strategies are employed. My favorite is the simplest--let a graphing calculator show you the zeros.
___
Descartes observed that the sign changes in the coefficients can tell you the number of real roots. This expression has two sign changes (+-+), so has 0 or 2 positive real roots. If the odd-degree terms have their signs changed, there is only one sign change (-++), so one negative real root.
It can also be informative to add the coefficients in both cases--as is, and with the odd-degree term signs changed. Here, the sum is zero in the first case, so we know immediately that x=1 is a zero of the expression. That is sufficient to help us reduce the problem to finding the zeros of the remaining quadratic factor.
__
Using synthetic division (or polynomial long division) to factor out x-1 (after removing the common factor of 4), we find the remaining quadratic factor to be x²+x-4.
The zeros of this quadratic factor can be found using the quadratic formula:
a=1, b=1, c=-4
x = (-b±√(b²-4ac))/(2a) = (-1±√1+16)/2
x = (-1 ±√17)2
The zeros are 1 and (-1±√17)/2.
_____
The graph shows the zeros of the expression. It also shows the quadratic after dividing out the factor (x-1). The vertex of that quadratic can be used to find the remaining solutions exactly: -0.5 ± √4.25.
__
The given expression factors as ...
4(x -1)(x² +x -4)