Answer:
neither
Here's how you know:
first, i'll simplify it so both are in slope-intercept form (y = mx + b).
x-3y=6
-3y = 6 - x
y = (1/3)x - 2
y=3x+4 is already in slope-intercept form, yay :)
these lines are neither parallel nor perpendicular.
The equations of parallel lines have THE SAME SLOPES (y = <em>m</em>x + b --> m would be exactly the same).
In contrast, perpendicular lines have NEGATIVE RECIPROCAL SLOPES (y = <em>m</em>x + b --> m would be <em>-1/m</em>).
<u><em>--> since the slopes of these match neither of these definitions, we know it must be neither.</em></u>
We know that:
∠ABC=∠BCA=xº
∠BDC=∠BCD=xº
1) we have to find the angle ∠DBC:
∠BDC+∠BCD+∠DBC=180º
xº+xº+∠DBC=180º
2xº+∠DBC=180º
∠DBC=180º-2xº
2) we have to find the angle ∠ABD:
∠ABD=∠ABC-∠DBC
∠ABD=xº-(180º-2x)
∠ABD=xº-180º+2xº
∠ABD=3xº-180º
Answer: ∠ABD=3xº-180º
Answer:
please answer mine
Step-by-step explanation:
Answer:
35
Step-by-step explanation:
Steps
1. 5x + 105 = 8x because you distributed the 5
2. 105 = 3x because you subtract the 5x on both sides
3. 105/3 = x because you divide the 3 and 105/3 is 35
Answer:
24
Step-by-step explanation:
(72/-9) / (-1/3)
72/-9) x (-3/1)
(72)*(-3) = - 216/ -9
= 24
